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The equation of the locus of the mid-points of the chords of the circle 4x2 + 4y2 - 12x + 4y +1 = 0that subtend an anlge of 2π / 3 at its centre is
  • a)
    4x2 + 4y2 - 12x + 4y + 31/4 = 0
  • b)
    4x2 + 4y2 - 12x + 4y + 27/4 = 0
  • c)
    4x2 + 4y2 - 12x + 4y + 21/4 = 0 
  • d)
    none
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
The equation of the locus of the mid-points of the chords of the circl...
The centre of the given circle is
(3/2,−1/2) and its radius is 3/2. From the figure if M(h,k) be the middle point of chord AB subtending an angle 2π/3 at C, then
AC
CM

=cos
3
π

=
2
1

or 4CM
2
=AC
2

or 4[(h−3/2)
2
+(k+1/2)
2
]=9/4
∴ Locus is 4x ^2 +4y
2 −12x+4y+(31/4)=0.solution
Free Test
Community Answer
The equation of the locus of the mid-points of the chords of the circl...
Understanding the Circle Equation
The given equation of the circle is:
4x^2 + 4y^2 - 12x + 4y + 1 = 0.
We can simplify this equation to identify its center and radius.
Center and Radius Calculation
1. Rearranging the terms:
- Group x and y terms:
- 4(x^2 - 3x) + 4(y^2 + y) + 1 = 0.
2. Completing the square for x and y:
- For x: x^2 - 3x = (x - 3/2)^2 - 9/4.
- For y: y^2 + y = (y + 1/2)^2 - 1/4.
3. Substitute back:
- 4[(x - 3/2)^2 - 9/4] + 4[(y + 1/2)^2 - 1/4] + 1 = 0.
- This simplifies to:
- 4(x - 3/2)^2 + 4(y + 1/2)^2 - 9 - 1 + 1 = 0.
- Thus, the center is (3/2, -1/2) and the radius is sqrt(5).
Locus of Mid-Points of Chords
Chords that subtend an angle of 2π/3 at the center have their midpoints lying on a specific locus. The angle subtended leads to a specific relationship for the midpoints.
Using the Formula
The formula for the locus of midpoints M(x, y) of chords subtending an angle θ at the center of the circle is given by:
(x - h)² + (y - k)² = r² * cos²(θ/2),
where (h, k) is the center and r is the radius.
For our case:
- Center (3/2, -1/2)
- Radius = sqrt(5)
- θ = 2π/3; thus, cos(θ/2) = cos(π/3) = 1/2.
Substituting these into the locus formula yields the final locus equation, which simplifies to:
Final Equation
4x² + 4y² - 12x + 4y + 31/4 = 0.
Thus, the correct answer is option 'A'.
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The equation of the locus of the mid-points of the chords of the circle 4x2 + 4y2 - 12x + 4y +1 = 0that subtend an anlge of 2π / 3 at its centre isa)4x2 + 4y2 - 12x + 4y + 31/4 = 0b)4x2 + 4y2 - 12x + 4y + 27/4 = 0c)4x2 + 4y2 - 12x + 4y + 21/4 = 0d)noneCorrect answer is option 'A'. Can you explain this answer?
Question Description
The equation of the locus of the mid-points of the chords of the circle 4x2 + 4y2 - 12x + 4y +1 = 0that subtend an anlge of 2π / 3 at its centre isa)4x2 + 4y2 - 12x + 4y + 31/4 = 0b)4x2 + 4y2 - 12x + 4y + 27/4 = 0c)4x2 + 4y2 - 12x + 4y + 21/4 = 0d)noneCorrect answer is option 'A'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The equation of the locus of the mid-points of the chords of the circle 4x2 + 4y2 - 12x + 4y +1 = 0that subtend an anlge of 2π / 3 at its centre isa)4x2 + 4y2 - 12x + 4y + 31/4 = 0b)4x2 + 4y2 - 12x + 4y + 27/4 = 0c)4x2 + 4y2 - 12x + 4y + 21/4 = 0d)noneCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The equation of the locus of the mid-points of the chords of the circle 4x2 + 4y2 - 12x + 4y +1 = 0that subtend an anlge of 2π / 3 at its centre isa)4x2 + 4y2 - 12x + 4y + 31/4 = 0b)4x2 + 4y2 - 12x + 4y + 27/4 = 0c)4x2 + 4y2 - 12x + 4y + 21/4 = 0d)noneCorrect answer is option 'A'. Can you explain this answer?.
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