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If the velocity of a body is doubled its kinetic energy
  • a)
    gets doubled
  • b)
    becomes half
  • c)
    does not change
  • d)
    becomes 4 times
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
If the velocity of a body is doubled its kinetic energya)gets doubledb...
In general if velocity is normal (or) 1time only,then K.E.=1/2 mv^2.
If velocity becomes 4 times then K.E.=1/2m(2v)^2=1/2m(4v^2)=2mv^2.
No. of times of normal velocity=2mv^2 ÷ 1/2mv^2=4.
So,if velocity is 2 times K.E. becomes 4 times.

(or)
From the formula of K.E. =1/2mv^2.
We can say that K.E. is directly proportional to v^2.(if mass is kept constant).
If v becomes 2times of actual velocity then,v^2=(2)^2=4 times.
Since K.E. is directly proportional to v^2.(if mass is kept constant).
So,K.E also becomes 4times of actual K.E.
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If the velocity of a body is doubled its kinetic energya)gets doubledb...
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If the velocity of a body is doubled its kinetic energya)gets doubledb)becomes halfc)does not changed)becomes 4 timesCorrect answer is option 'D'. Can you explain this answer?
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