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In a G.P. of even number of terms, the sum of all terms is 5 times the sum of odd terms. The common ratio of the G.P is?
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Sum of all terms in the G.P
- Let's assume the G.P has n terms, so the sum of all terms can be calculated using the formula:
S = a(r^n - 1) / (r - 1)
where S is the sum, a is the first term, r is the common ratio, and n is the number of terms.

Sum of odd terms in the G.P
- In a G.P with n terms, the odd terms are a, a*r^2, a*r^4, ... and the sum of these terms can be calculated using the formula:
S_odd = a(1 + r^2 + r^4 + ...) = a / (1 - r^2)

Given condition
- The sum of all terms is 5 times the sum of odd terms, so we have:
S = 5S_odd
a(r^n - 1) / (r - 1) = 5a / (1 - r^2)

Solving for common ratio (r)
- By simplifying the above equation, we get:
r^n - 1 = 5(1 - r^2)
r^n - 1 = 5 - 5r^2
r^n + 5r^2 = 6
- Since the number of terms in a G.P is even, let's assume n = 2m. Substituting this in the equation:
r^(2m) + 5r^2 = 6
r^2(1 + 5) = 6
r^2 = 6 / 6
r^2 = 1
r = 1 or -1

Conclusion
- The common ratio for the G.P can be either 1 or -1.
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In a G.P. of even number of terms, the sum of all terms is 5 times the sum of odd terms. The common ratio of the G.P is?
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