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Certain bulb 'A' containing gas at 1.5 bar pressure was put into communication with an evacuated vessel of 1.0 dmcube capacity through the stop cock. The final pressure of the system dropped to 920mbar, at the same temperature. What is the volume of the container A?
Most Upvoted Answer
Certain bulb 'A' containing gas at 1.5 bar pressure was put into commu...
Given:
- Initial pressure in bulb A, P1 = 1.5 bar
- Final pressure in the system, P2 = 920 mbar = 0.92 bar
- Volume of the evacuated vessel, V2 = 1.0 dm³

To Find:
- Volume of bulb A, V1 = ?

Formula:
- Boyle's Law: P1 * V1 = P2 * V2

Solution:
Let's calculate the volume of bulb A using Boyle's Law.

Step 1: Convert the pressure from mbar to bar
- P2 = 920 mbar = 0.92 bar

Step 2: Substitute the values into the Boyle's Law equation
- P1 * V1 = P2 * V2
- 1.5 bar * V1 = 0.92 bar * 1.0 dm³

Step 3: Rearrange the equation to solve for V1
- V1 = (P2 * V2) / P1
- V1 = (0.92 bar * 1.0 dm³) / 1.5 bar

Step 4: Calculate the volume of bulb A
- V1 = 0.6133 dm³

Answer:
The volume of bulb A is 0.6133 dm³.
Community Answer
Certain bulb 'A' containing gas at 1.5 bar pressure was put into commu...
V1/v2=t1/t2
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Certain bulb 'A' containing gas at 1.5 bar pressure was put into communication with an evacuated vessel of 1.0 dmcube capacity through the stop cock. The final pressure of the system dropped to 920mbar, at the same temperature. What is the volume of the container A?
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