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the constant force resisting the motion of car of mass 1500kg is equal to one fifteen if it's weight if when traveling@48kmph car is bought to rest in a distance of 50m by applying brakes find additional retarding force due to brakes(assume constant) and heat developed in brakes
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? the constant force resisting the motion of car of mass 1500kg is equ...
Ans.
V = 48km/hr
V = 40/3 = 13.33 m/s
v^2 - u^2 = 2as
0 - (40/3)^2 = 2*a*50
a = -16/9
|a| = 16/9 m/s^2
But a = 1/15(g) + additional acceleration
additional acceleration = 16/9 - 1/15(9.81)
additional acceleration = 1.12377
f = ma
additional force = m* additional acceleration
additional force = 1500*1.12377
= 1685.667 kg.m/s^2
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? the constant force resisting the motion of car of mass 1500kg is equ...
Given:
Mass of the car (m) = 1500 kg
Initial velocity (u) = 48 km/h = 13.33 m/s
Final velocity (v) = 0 m/s
Distance traveled (s) = 50 m
Step 1: Finding the weight of the car:
Weight (W) = mass × acceleration due to gravity
W = 1500 kg × 9.8 m/s²
W = 14700 N
Step 2: Calculating the resisting force:
The constant force resisting the motion of the car is equal to one-fifteenth of its weight.
Resisting force = (1/15) × Weight
Resisting force = (1/15) × 14700 N
Resisting force = 980 N
Step 3: Finding the additional retarding force due to brakes:
To find the additional retarding force due to brakes, we need to calculate the net force acting on the car.
Net force = mass × acceleration
Since the car comes to rest, the final velocity (v) is 0 m/s. Therefore, the acceleration (a) can be calculated using the equation:
v² = u² + 2as
0 = (13.33 m/s)² + 2a × 50 m
0 = 177.76 m²/s² + 100a
100a = -177.76 m²/s²
a = -1.7776 m/s² (negative sign indicates deceleration)
Net force = mass × acceleration
Additional retarding force due to brakes = net force - resisting force
Additional retarding force = (1500 kg) × (-1.7776 m/s²) - 980 N
Additional retarding force = -2666.4 N - 980 N
Additional retarding force = -3646.4 N (negative sign indicates opposing motion)
Step 4: Calculating the heat developed in brakes:
The heat developed in the brakes can be calculated using the formula:
Heat = force × distance
Heat developed in brakes = additional retarding force × distance traveled
Heat developed in brakes = -3646.4 N × 50 m
Heat developed in brakes = -182,320 J (negative sign indicates energy lost as heat)
Conclusion:
The additional retarding force due to brakes is approximately -3646.4 N (opposing motion) and the heat developed in the brakes is approximately -182,320 J (energy lost as heat). The negative signs indicate opposing motion and energy loss.
Mass of the car (m) = 1500 kg
Initial velocity (u) = 48 km/h = 13.33 m/s
Final velocity (v) = 0 m/s
Distance traveled (s) = 50 m
Step 1: Finding the weight of the car:
Weight (W) = mass × acceleration due to gravity
W = 1500 kg × 9.8 m/s²
W = 14700 N
Step 2: Calculating the resisting force:
The constant force resisting the motion of the car is equal to one-fifteenth of its weight.
Resisting force = (1/15) × Weight
Resisting force = (1/15) × 14700 N
Resisting force = 980 N
Step 3: Finding the additional retarding force due to brakes:
To find the additional retarding force due to brakes, we need to calculate the net force acting on the car.
Net force = mass × acceleration
Since the car comes to rest, the final velocity (v) is 0 m/s. Therefore, the acceleration (a) can be calculated using the equation:
v² = u² + 2as
0 = (13.33 m/s)² + 2a × 50 m
0 = 177.76 m²/s² + 100a
100a = -177.76 m²/s²
a = -1.7776 m/s² (negative sign indicates deceleration)
Net force = mass × acceleration
Additional retarding force due to brakes = net force - resisting force
Additional retarding force = (1500 kg) × (-1.7776 m/s²) - 980 N
Additional retarding force = -2666.4 N - 980 N
Additional retarding force = -3646.4 N (negative sign indicates opposing motion)
Step 4: Calculating the heat developed in brakes:
The heat developed in the brakes can be calculated using the formula:
Heat = force × distance
Heat developed in brakes = additional retarding force × distance traveled
Heat developed in brakes = -3646.4 N × 50 m
Heat developed in brakes = -182,320 J (negative sign indicates energy lost as heat)
Conclusion:
The additional retarding force due to brakes is approximately -3646.4 N (opposing motion) and the heat developed in the brakes is approximately -182,320 J (energy lost as heat). The negative signs indicate opposing motion and energy loss.
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? the constant force resisting the motion of car of mass 1500kg is equal to one fifteen if it's weight if when traveling@48kmph car is bought to rest in a distance of 50m by applying brakes find additional retarding force due to brakes(assume constant) and heat developed in brakes
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? the constant force resisting the motion of car of mass 1500kg is equal to one fifteen if it's weight if when traveling@48kmph car is bought to rest in a distance of 50m by applying brakes find additional retarding force due to brakes(assume constant) and heat developed in brakes for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about ? the constant force resisting the motion of car of mass 1500kg is equal to one fifteen if it's weight if when traveling@48kmph car is bought to rest in a distance of 50m by applying brakes find additional retarding force due to brakes(assume constant) and heat developed in brakes covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for ? the constant force resisting the motion of car of mass 1500kg is equal to one fifteen if it's weight if when traveling@48kmph car is bought to rest in a distance of 50m by applying brakes find additional retarding force due to brakes(assume constant) and heat developed in brakes.
? the constant force resisting the motion of car of mass 1500kg is equal to one fifteen if it's weight if when traveling@48kmph car is bought to rest in a distance of 50m by applying brakes find additional retarding force due to brakes(assume constant) and heat developed in brakes for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about ? the constant force resisting the motion of car of mass 1500kg is equal to one fifteen if it's weight if when traveling@48kmph car is bought to rest in a distance of 50m by applying brakes find additional retarding force due to brakes(assume constant) and heat developed in brakes covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for ? the constant force resisting the motion of car of mass 1500kg is equal to one fifteen if it's weight if when traveling@48kmph car is bought to rest in a distance of 50m by applying brakes find additional retarding force due to brakes(assume constant) and heat developed in brakes.
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