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A man standing in front of a large wall claps two objects against each other at an Interval of 1.2 seconds regularly. The echo of first clap coincides with the fifth clap. If the speed of sound in air is 340m/sec, the distance between the man and the wall is.????
Verified Answer
A man standing in front of a large wall claps two objects against each...
The fifth clap happens 1.2x4=4.8 sec after the first clap. 
In this time interval, the sound travels 340x4.8=1632 m,
So the wall is 16322/=816 m away from the man.
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A man standing in front of a large wall claps two objects against each...
Problem Analysis:

- The man is clapping two objects against each other at an interval of 1.2 seconds.
- The echo of the first clap coincides with the fifth clap.
- The speed of sound in air is 340 m/sec.

Solution:

To find the distance between the man and the wall, we need to consider the time it takes for the sound to travel from the man to the wall and back as well as the time interval between the claps.

Let's assume the time it takes for the sound to travel from the man to the wall and back as "t" seconds.

The time interval between the claps is 1.2 seconds.

Clap and Echo:

When the man claps for the first time, the sound wave travels to the wall and back, reaching the man again. This is the echo of the first clap.

Similarly, when the man claps for the fifth time, the sound wave travels to the wall and back, reaching the man again. This is the echo of the fifth clap.

Since the echo of the first clap coincides with the echo of the fifth clap, the time taken for the sound to travel from the man to the wall and back is the same for the first clap and the fifth clap.

Therefore, the time taken for the sound to travel from the man to the wall and back is (1.2 * 4) seconds.

Calculating Distance:

We can use the formula: distance = speed * time

Given that the speed of sound in air is 340 m/sec and the time taken for the sound to travel from the man to the wall and back is (1.2 * 4) seconds, we can calculate the distance as follows:

distance = 340 * (1.2 * 4)

distance = 340 * 4.8

distance = 1632 meters

Therefore, the distance between the man and the wall is 1632 meters.
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A man standing in front of a large wall claps two objects against each other at an Interval of 1.2 seconds regularly. The echo of first clap coincides with the fifth clap. If the speed of sound in air is 340m/sec, the distance between the man and the wall is.????
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