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A steady current in a straight conducting wire produces a surface charge on it. Let Eout and Ein be the magnitudes of the electric fields just outside and just inside the wire, respectively. W hich of the following statements is true for these fields ?
- a)Eout is always greater than Ein
- b)Eout is always smaller than Ein
- c)Eout could be greater or smaller than Ein
- d)Eout is equal to Ein
Correct answer is option 'A'. Can you explain this answer?
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A steady current in a straight conducting wire produces a surface char...
Explanation:
When a steady current flows through a straight conducting wire, it produces a surface charge on the wire. This surface charge creates an electric field just outside and just inside the wire.
Ein and Eout:
Ein is the electric field just inside the wire, and Eout is the electric field just outside the wire. These fields are related to each other by Gauss's law.
Gauss's Law:
Gauss's law states that the electric flux through any closed surface is proportional to the charge enclosed by the surface. In the case of a straight conducting wire, the charge enclosed by the surface is zero. Therefore, the electric flux through any closed surface is zero.
The electric field just inside the wire:
The electric field just inside the wire is perpendicular to the surface of the wire. This electric field is equal to the surface charge density divided by the permittivity of free space.
The electric field just outside the wire:
The electric field just outside the wire is also perpendicular to the surface of the wire. This electric field is proportional to the current in the wire and inversely proportional to the distance from the wire.
Conclusion:
From the above explanation, we can conclude that Eout is always greater than Ein. This is because the electric field just outside the wire is proportional to the current in the wire, whereas the electric field just inside the wire is proportional to the surface charge density. Since the current in the wire is greater than the surface charge density, Eout is always greater than Ein. Therefore, option A is the correct answer.
When a steady current flows through a straight conducting wire, it produces a surface charge on the wire. This surface charge creates an electric field just outside and just inside the wire.
Ein and Eout:
Ein is the electric field just inside the wire, and Eout is the electric field just outside the wire. These fields are related to each other by Gauss's law.
Gauss's Law:
Gauss's law states that the electric flux through any closed surface is proportional to the charge enclosed by the surface. In the case of a straight conducting wire, the charge enclosed by the surface is zero. Therefore, the electric flux through any closed surface is zero.
The electric field just inside the wire:
The electric field just inside the wire is perpendicular to the surface of the wire. This electric field is equal to the surface charge density divided by the permittivity of free space.
The electric field just outside the wire:
The electric field just outside the wire is also perpendicular to the surface of the wire. This electric field is proportional to the current in the wire and inversely proportional to the distance from the wire.
Conclusion:
From the above explanation, we can conclude that Eout is always greater than Ein. This is because the electric field just outside the wire is proportional to the current in the wire, whereas the electric field just inside the wire is proportional to the surface charge density. Since the current in the wire is greater than the surface charge density, Eout is always greater than Ein. Therefore, option A is the correct answer.
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A steady current in a straight conducting wire produces a surface char...
Continuity equation based on conservation of charge where for steady current condition is del.J=0 which means constant and if there is no volume charge density inside the wire how can be the Electric there so electric field inside the wire is zero and out side not
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A steady current in a straight conducting wire produces a surface charge on it. Let Eout and Ein be the magnitudes of the electric fields just outside and just inside the wire, respectively. W hich of the following statements is true for these fields ?a)Eout is always greater than Einb)Eout is always smaller than Einc)Eout could be greater or smaller than Eind)Eout is equal to EinCorrect answer is option 'A'. Can you explain this answer?
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A steady current in a straight conducting wire produces a surface charge on it. Let Eout and Ein be the magnitudes of the electric fields just outside and just inside the wire, respectively. W hich of the following statements is true for these fields ?a)Eout is always greater than Einb)Eout is always smaller than Einc)Eout could be greater or smaller than Eind)Eout is equal to EinCorrect answer is option 'A'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about A steady current in a straight conducting wire produces a surface charge on it. Let Eout and Ein be the magnitudes of the electric fields just outside and just inside the wire, respectively. W hich of the following statements is true for these fields ?a)Eout is always greater than Einb)Eout is always smaller than Einc)Eout could be greater or smaller than Eind)Eout is equal to EinCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A steady current in a straight conducting wire produces a surface charge on it. Let Eout and Ein be the magnitudes of the electric fields just outside and just inside the wire, respectively. W hich of the following statements is true for these fields ?a)Eout is always greater than Einb)Eout is always smaller than Einc)Eout could be greater or smaller than Eind)Eout is equal to EinCorrect answer is option 'A'. Can you explain this answer?.
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