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If the position vectors of A and B are i+3j-k and 3i-j-3k respectively, then the position vector of mid point of AB isOptions
  • a)
    i+2j-k
  • b)
    2i+j-2k
  • c)
    2i+j-k
  • d)
    i+j-2k
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
If the position vectors of A and B are i+3j-k and 3i-j-3k respectively...
Explanation:
To find the midpoint of AB, we need to use the formula:

Midpoint of AB = (Position vector of A + Position vector of B)/2

Given position vectors of A and B are:

A = i + 3j - k
B = 3i - j - 3k

Step 1: Add the position vectors of A and B

A + B = (i + 3j - k) + (3i - j - 3k)
= 4i + 2j - 4k

Step 2: Divide the sum of position vectors by 2 to get the midpoint

Midpoint of AB = (A + B)/2
= (4i + 2j - 4k)/2
= 2i + j - 2k

Therefore, the position vector of the midpoint of AB is 2i + j - 2k. Hence, the correct answer is option B.
Free Test
Community Answer
If the position vectors of A and B are i+3j-k and 3i-j-3k respectively...
Just add A and B vectors and divide that by 2. You will get it
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Question Description
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