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If initial concentration is reduced to (1/4)th in a zero order reaction, the time taken for half the reaction to complete
  • a)
    remains same
  • b)
    becomes 4 times
  • c)
    becomes one-fourth
  • d)
    doubles
Correct answer is option 'C'. Can you explain this answer?
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If initial concentration is reduced to (1/4)th in a zero order reactio...
Explanation:

In a zero-order reaction, the rate of reaction is independent of the concentration of reactants. It means that the rate of reaction remains constant throughout the reaction.

Given, the initial concentration is reduced to (1/4)th. It means that the concentration of reactant becomes one-fourth of its initial concentration.

Now, we need to find the time taken for half the reaction to complete.

Let's assume that the initial concentration of reactant is 'A' and its rate of reaction is 'k'. Therefore, the rate equation for the zero-order reaction is given by:

Rate = k[A]^0 = k

After reducing the initial concentration to (1/4)th, the new concentration of reactant becomes 'A/4'. Therefore, the new rate of reaction is given by:

Rate' = k[A/4]^0 = k

We know that the time taken for half the reaction to complete is given by:

t1/2 = [A]0 / 2k

where [A]0 is the initial concentration of reactant.

Now, let's calculate the time taken for half the reaction to complete after reducing the initial concentration to (1/4)th.

t1/2' = [A/4]0 / 2k

= ([A]0 / 4) / 2k

= [A]0 / 8k

Therefore, we can see that the time taken for half the reaction to complete becomes one-fourth of its initial value. Hence, the correct option is C.

Summary:

- In a zero-order reaction, the rate of reaction is independent of the concentration of reactants.
- The time taken for half the reaction to complete is given by t1/2 = [A]0 / 2k, where [A]0 is the initial concentration of reactant and k is the rate constant.
- After reducing the initial concentration to (1/4)th, the time taken for half the reaction to complete becomes one-fourth of its initial value.
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If initial concentration is reduced to (1/4)th in a zero order reaction, the time taken for half the reaction to completea)remains sameb)becomes 4 timesc)becomes one-fourthd)doublesCorrect answer is option 'C'. Can you explain this answer?
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