In the figure the variation of potential energy of a particle of mass m = 2kg is represented w.r.t. its x-coordinate. The particle moves under the effect of this conservative force along the x-axis.Q.If the particle is released at the origin then :a)it will move towards positive x-axis.b)it will move towards negative x-axis.c)it will remain stationary at the origin.d)its subsequent motion cannot be decided due to lack of information.Correct answer is option 'B'. Can you explain this answer?

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In the figure the variation of potential energy of a particle of mass m = 2kg is represented w.r.t. its x-coordinate. The particle moves under the effect of this conservative force along the x-axis.

Q. If the particle is released at the origin then :

a)
it will move towards positive x-axis.
b)
it will move towards negative x-axis.
c)
it will remain stationary at the origin.
d)
its subsequent motion cannot be decided due to lack of information.

Correct answer is option 'B'. Can you explain this answer?

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In the figure the variation of potential energy of a particle of mass ...

If the particle is released at the origin, it will try to go in the direction of force. Here

is positive and
hence force is negative, as a result it will move towards – ve x-axis.

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In the figure the variation of potential energy of a particle of mass m = 2kg is represented w.r.t. its x-coordinate. The particle moves under the effect of this conservative force along the x-axis.Q.If the particle is released at the origin then :a)it will move towards positive x-axis.b)it will move towards negative x-axis.c)it will remain stationary at the origin.d)its subsequent motion cannot be decided due to lack of information.Correct answer is option 'B'. Can you explain this answer?

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In the figure the variation of potential energy of a particle of mass m = 2kg is represented w.r.t. its x-coordinate. The particle moves under the effect of this conservative force along the x-axis.Q.If the particle is released at the origin then :a)it will move towards positive x-axis.b)it will move towards negative x-axis.c)it will remain stationary at the origin.d)its subsequent motion cannot be decided due to lack of information.Correct answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about In the figure the variation of potential energy of a particle of mass m = 2kg is represented w.r.t. its x-coordinate. The particle moves under the effect of this conservative force along the x-axis.Q.If the particle is released at the origin then :a)it will move towards positive x-axis.b)it will move towards negative x-axis.c)it will remain stationary at the origin.d)its subsequent motion cannot be decided due to lack of information.Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In the figure the variation of potential energy of a particle of mass m = 2kg is represented w.r.t. its x-coordinate. The particle moves under the effect of this conservative force along the x-axis.Q.If the particle is released at the origin then :a)it will move towards positive x-axis.b)it will move towards negative x-axis.c)it will remain stationary at the origin.d)its subsequent motion cannot be decided due to lack of information.Correct answer is option 'B'. Can you explain this answer?.

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