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In the truth table of an N-input OR gate, in the column for the output of the gate,
- a)the number of zeros is equal to N.
- b)the number of zeros is always 1.
- c)the output is zero if any one of the input is zero
- d)the number of times a zero occurs is a complex function of N.
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
In the truth table of an N-input OR gate, in the column for the output...
A two input OR gate truth table is shown below:
From the truth table of OR gate it is clear tha output is 0’s only when all the inputs are 0’s otherwise for all other input combination outpu is always 1's. Hence, in the column for the outpu of the OR gate, the number of zeros is always 1's.
From the truth table of OR gate it is clear tha output is 0’s only when all the inputs are 0’s otherwise for all other input combination outpu is always 1's. Hence, in the column for the outpu of the OR gate, the number of zeros is always 1's.
Most Upvoted Answer
In the truth table of an N-input OR gate, in the column for the output...
Explanation:
Output of an N-input OR gate:
An N-input OR gate produces a HIGH output if any of its inputs are HIGH. In other words, the output is LOW only if all the inputs are LOW.
Truth table of an N-input OR gate:
In the truth table of an N-input OR gate, the number of zeros in the output column is always 1. This is because for the output to be zero, all the inputs must be zero. If any one of the inputs is HIGH, the output will be HIGH.
Example:
Let's take an example of a 3-input OR gate:
| Input A | Input B | Input C | Output |
|---------|---------|---------|--------|
| 0 | 0 | 0 | 0 |
| 0 | 0 | 1 | 1 |
| 0 | 1 | 0 | 1 |
| 0 | 1 | 1 | 1 |
| 1 | 0 | 0 | 1 |
| 1 | 0 | 1 | 1 |
| 1 | 1 | 0 | 1 |
| 1 | 1 | 1 | 1 |
In this truth table, there is only one occurrence of 0 in the output column, which corresponds to the case where all inputs are 0.
Therefore, the correct statement is option B: the number of zeros in the output column is always 1.
Output of an N-input OR gate:
An N-input OR gate produces a HIGH output if any of its inputs are HIGH. In other words, the output is LOW only if all the inputs are LOW.
Truth table of an N-input OR gate:
In the truth table of an N-input OR gate, the number of zeros in the output column is always 1. This is because for the output to be zero, all the inputs must be zero. If any one of the inputs is HIGH, the output will be HIGH.
Example:
Let's take an example of a 3-input OR gate:
| Input A | Input B | Input C | Output |
|---------|---------|---------|--------|
| 0 | 0 | 0 | 0 |
| 0 | 0 | 1 | 1 |
| 0 | 1 | 0 | 1 |
| 0 | 1 | 1 | 1 |
| 1 | 0 | 0 | 1 |
| 1 | 0 | 1 | 1 |
| 1 | 1 | 0 | 1 |
| 1 | 1 | 1 | 1 |
In this truth table, there is only one occurrence of 0 in the output column, which corresponds to the case where all inputs are 0.
Therefore, the correct statement is option B: the number of zeros in the output column is always 1.
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