A and B invest some money in a business in the ratio of 9 : 11. If the total money invested is Rs. 6480. Find how much amount B invested more than A?a)Rs. 648b)Rs. 326c)Rs. 864d)Rs. 742Correct answer is option 'A'. Can you explain this answer?

Question

Answer

Given information:
- A and B invest some money in a business in the ratio of 9:11
- Total money invested is Rs. 6480

To find:
- Amount B invested more than A

Solution:
Let's assume that A invested Rs. 9x and B invested Rs. 11x (as per the given ratio)
Total money invested = Rs. 6480
So, 9x + 11x = 6480
20x = 6480
x = 324

Therefore, A invested = 9x = 9 * 324 = Rs. 2916
And, B invested = 11x = 11 * 324 = Rs. 3564

Amount B invested more than A = Rs. (3564 - 2916) = Rs. 648

Hence, the correct answer is option A (Rs. 648).

Note: It's important to understand the concept of ratios and their application in solving such problems. The total investment is divided into parts based on the ratio, and then we can calculate the exact amount invested by each person. Finally, we can find the difference between the amounts invested by A and B to get the answer.

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