One mole of an ideal gas with average molecular speed v0 is kept in a ...
For fixed volume if temperature is increased then pressure is also increased by same amount so mean free path will not change.
λ = kT / √2πd2P
View all questions of this test
One mole of an ideal gas with average molecular speed v0 is kept in a ...
Explanation:
In this question, we are given that we have an ideal gas with average molecular speed v0 and its temperature is increased such that the average speed gets doubled. We need to find the effect of this temperature increase on the mean free path of gas molecules.
Mean Free Path: The mean free path of a gas molecule is the average distance travelled by a molecule between two successive collisions.
Effect of Temperature on Mean Free Path: The mean free path of gas molecules is inversely proportional to the number of collisions. The temperature increase increases the kinetic energy of gas molecules, so they move faster and collide more frequently. As a result, the mean free path decreases. Conversely, if the temperature decreases, then the mean free path increases.
Answer: Option 'B' - the mean free path of the gas molecule will not change.
Explanation: In the given question, we are told that the average molecular speed of the gas is doubled. However, it is not specified whether the temperature is increased or not. Therefore, we cannot apply the relationship between temperature and the mean free path to solve this question.
We know that the mean free path of a gas molecule depends on the size of the gas molecules and the density of the gas. It is independent of the speed of the gas molecules. Therefore, if the speed of the gas molecules is doubled, it will not affect the mean free path of the gas molecules.
Collision Frequency: The collision frequency of gas molecules with the wall of the container is proportional to the speed of the gas molecules. Therefore, if the speed of the gas molecules is doubled, then the collision frequency of the gas molecules with the wall of the container will also double.
Conclusion: Therefore, the correct answer is option 'B' - the mean free path of the gas molecule will not change.