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An engine produces 10 kW brake power while working with a brake thermal efficiency of 30%. If the calorific value of the fuel used is 40,000 kJ/kg then what is the fuel consumption?
  • a)
    1.5 kg/hour
  • b)
    3.0 kg/hour
  • c)
    0.3 kg/hour
  • d)
    1.0 kg/hou
Correct answer is option 'B'. Can you explain this answer?
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An engine produces 10 kW brake power while working with a brake therma...
Given data:
Brake power (P_b) = 10 kW
Brake thermal efficiency (η_b) = 30% = 0.3
Calorific value of the fuel (CV) = 40,000 kJ/kg

Fuel consumption (m_f) can be calculated using the formula:

m_f = P_b / (CV * η_b)

Calculations:
m_f = 10 / (40,000 * 0.3) = 0.0833 kg/s
Converting to kg/hour: 0.0833 * 3600 = 300 kg/hour

Therefore, the fuel consumption of the engine is 3.0 kg/hour (option B).
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An engine produces 10 kW brake power while working with a brake thermal efficiency of 30%. If the calorific value of the fuel used is 40,000 kJ/kg then what is the fuel consumption?a)1.5 kg/hourb)3.0 kg/hourc)0.3 kg/hourd)1.0 kg/houCorrect answer is option 'B'. Can you explain this answer?
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