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Find the remainder when 3x2 – 6x2 3x -7÷9 is divided by 3x – 4.​?
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Find the remainder when 3x2 – 6x2 3x -7÷9 is divided by 3x – 4.​?
Problem: Find the remainder when 3x2 – 6x2 + 3x - 7 is divided by 3x – 4.

Solution:
In order to find the remainder, we can use the polynomial long division method.

Step 1: Write the polynomial in standard form.

3x2 – 6x2 + 3x - 7

Step 2: Divide the first term of the polynomial by the first term of the divisor.

3x2 ÷ 3x = x

Step 3: Multiply the divisor by the quotient obtained in Step 2.

3x – 4 * x = 3x2 - 4x

Step 4: Subtract the result from Step 3 from the polynomial in standard form.

(3x2 – 6x2 + 3x - 7) - (3x2 - 4x) = -2x - 7

Step 5: Repeat Steps 2-4 with the remainder obtained in Step 4.

-2x ÷ 3x = -2/3

3x – 4 * (-2/3) = -2

(-2x - 7) - (-2) = -2x - 5

Step 6: The remainder is -2x - 5.

Therefore, the remainder when 3x2 – 6x2 + 3x - 7 is divided by 3x – 4 is -2x - 5.
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Find the remainder when 3x2 – 6x2 3x -7÷9 is divided by 3x – 4.​?
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Find the remainder when 3x2 – 6x2 3x -7÷9 is divided by 3x – 4.​?
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