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There will be three different flourine-flourine distances in molecule CF2(C)2CF2. Assuming ideal bond angles for a particular hybridisation (assume no distortion due to double bonds) find out the smaller flourine-flourine distance and fill the result (in pm) in the increasing order in your answer sheet. Round off your answer to the nearest whole number.
(Given that C–F bond length = 134 pm, C=C bond length = 134 pm √3 = 1.73)
Correct answer is '232'. Can you explain this answer?
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To determine the smaller fluorine-fluorine distance in the molecule CF2(C)2CF2, we need to consider the ideal bond angles and hybridization.
In this molecule, the central carbon atom (C) is bonded to two fluorine atoms (F), and each of the fluorine atoms is also bonded to two carbon atoms (C).
The carbon atom in the center is sp2 hybridized, which means it forms three sigma bonds in a trigonal planar arrangement with bond angles of 120 degrees.
The fluorine atoms are also sp2 hybridized since they are bonded to carbon atoms. Therefore, they also have bond angles of 120 degrees.
Now, let's consider the possible fluorine-fluorine distances in the molecule.
1. The fluorine atoms bonded to the same carbon atom (C) will have the shortest distance. This is because they are directly bonded to each other and are in a linear arrangement. The bond length of a fluorine-fluorine single bond is approximately 142 pm.
2. The fluorine atoms bonded to neighboring carbon atoms (C) will have a longer distance between them. The bond length of a fluorine-fluorine single bond is approximately 142 pm.
Therefore, the smaller fluorine-fluorine distance is 142 pm.
Round off the answer to the nearest whole number: 142 pm.
In this molecule, the central carbon atom (C) is bonded to two fluorine atoms (F), and each of the fluorine atoms is also bonded to two carbon atoms (C).
The carbon atom in the center is sp2 hybridized, which means it forms three sigma bonds in a trigonal planar arrangement with bond angles of 120 degrees.
The fluorine atoms are also sp2 hybridized since they are bonded to carbon atoms. Therefore, they also have bond angles of 120 degrees.
Now, let's consider the possible fluorine-fluorine distances in the molecule.
1. The fluorine atoms bonded to the same carbon atom (C) will have the shortest distance. This is because they are directly bonded to each other and are in a linear arrangement. The bond length of a fluorine-fluorine single bond is approximately 142 pm.
2. The fluorine atoms bonded to neighboring carbon atoms (C) will have a longer distance between them. The bond length of a fluorine-fluorine single bond is approximately 142 pm.
Therefore, the smaller fluorine-fluorine distance is 142 pm.
Round off the answer to the nearest whole number: 142 pm.
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There will be three different flourine-flourine distances in molecule CF2(C)2CF2. Assuming ideal bond angles for a particular hybridisation (assume no distortion due to double bonds) find out the smaller flourine-flourine distance and fill the result (in pm) in the increasing order in your answer sheet. Round off your answer to the nearest whole number.(Given that C–F bond length = 134 pm, C=C bond length = 134 pm √3= 1.73)Correct answer is '232'. Can you explain this answer?
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There will be three different flourine-flourine distances in molecule CF2(C)2CF2. Assuming ideal bond angles for a particular hybridisation (assume no distortion due to double bonds) find out the smaller flourine-flourine distance and fill the result (in pm) in the increasing order in your answer sheet. Round off your answer to the nearest whole number.(Given that C–F bond length = 134 pm, C=C bond length = 134 pm √3= 1.73)Correct answer is '232'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about There will be three different flourine-flourine distances in molecule CF2(C)2CF2. Assuming ideal bond angles for a particular hybridisation (assume no distortion due to double bonds) find out the smaller flourine-flourine distance and fill the result (in pm) in the increasing order in your answer sheet. Round off your answer to the nearest whole number.(Given that C–F bond length = 134 pm, C=C bond length = 134 pm √3= 1.73)Correct answer is '232'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for There will be three different flourine-flourine distances in molecule CF2(C)2CF2. Assuming ideal bond angles for a particular hybridisation (assume no distortion due to double bonds) find out the smaller flourine-flourine distance and fill the result (in pm) in the increasing order in your answer sheet. Round off your answer to the nearest whole number.(Given that C–F bond length = 134 pm, C=C bond length = 134 pm √3= 1.73)Correct answer is '232'. Can you explain this answer?.
There will be three different flourine-flourine distances in molecule CF2(C)2CF2. Assuming ideal bond angles for a particular hybridisation (assume no distortion due to double bonds) find out the smaller flourine-flourine distance and fill the result (in pm) in the increasing order in your answer sheet. Round off your answer to the nearest whole number.(Given that C–F bond length = 134 pm, C=C bond length = 134 pm √3= 1.73)Correct answer is '232'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about There will be three different flourine-flourine distances in molecule CF2(C)2CF2. Assuming ideal bond angles for a particular hybridisation (assume no distortion due to double bonds) find out the smaller flourine-flourine distance and fill the result (in pm) in the increasing order in your answer sheet. Round off your answer to the nearest whole number.(Given that C–F bond length = 134 pm, C=C bond length = 134 pm √3= 1.73)Correct answer is '232'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for There will be three different flourine-flourine distances in molecule CF2(C)2CF2. Assuming ideal bond angles for a particular hybridisation (assume no distortion due to double bonds) find out the smaller flourine-flourine distance and fill the result (in pm) in the increasing order in your answer sheet. Round off your answer to the nearest whole number.(Given that C–F bond length = 134 pm, C=C bond length = 134 pm √3= 1.73)Correct answer is '232'. Can you explain this answer?.
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