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Heat is being transferred convectively flow through a cylindrical nuclear reactor fuel rod of 50 mm diameter to water at 75°C. Under steady state condition, the rate of heat generation within the fuel element is 5 x107W/m3 and the. convection heat transfer coefficient is 1 kW/m2 K. The outer surface temperature of the fuel element would be
- a)700°C
- b)625°C
- c)550°C
- d)400°C
Correct answer is option 'A'. Can you explain this answer?
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°C. The outer surface of the fuel rod is maintained at a constant temperature of 200 °C. The thermal conductivity of the fuel rod material is 20 W/m·K, and the convective heat transfer coefficient between the fuel rod surface and the water is 1000 W/m²·K. Assuming steady-state conditions and neglecting heat generation within the fuel rod, determine the rate of heat transfer from the fuel rod to the water.
To calculate the rate of heat transfer from the fuel rod to the water, we can use the equation for convective heat transfer:
Q = h * A * (T_s - T_f)
Where:
Q is the rate of heat transfer
h is the convective heat transfer coefficient
A is the surface area of the fuel rod
T_s is the temperature of the water
T_f is the temperature of the fuel rod surface
First, we need to calculate the surface area of the fuel rod. The surface area of a cylinder can be calculated using the formula:
A = 2πrL + πr^2
Where:
r is the radius of the fuel rod (50 mm / 2 = 25 mm = 0.025 m)
L is the length of the fuel rod (assumed to be known, but not provided in the question)
Assuming an arbitrary length of 1 meter for the fuel rod, we can calculate the surface area as follows:
A = 2π(0.025)(1) + π(0.025)^2
A = 0.314 m²
Now we can substitute the given values into the equation for convective heat transfer:
Q = (1000)(0.314)(200 - 75)
Q = 31400 W
Therefore, the rate of heat transfer from the fuel rod to the water is 31400 W.
To calculate the rate of heat transfer from the fuel rod to the water, we can use the equation for convective heat transfer:
Q = h * A * (T_s - T_f)
Where:
Q is the rate of heat transfer
h is the convective heat transfer coefficient
A is the surface area of the fuel rod
T_s is the temperature of the water
T_f is the temperature of the fuel rod surface
First, we need to calculate the surface area of the fuel rod. The surface area of a cylinder can be calculated using the formula:
A = 2πrL + πr^2
Where:
r is the radius of the fuel rod (50 mm / 2 = 25 mm = 0.025 m)
L is the length of the fuel rod (assumed to be known, but not provided in the question)
Assuming an arbitrary length of 1 meter for the fuel rod, we can calculate the surface area as follows:
A = 2π(0.025)(1) + π(0.025)^2
A = 0.314 m²
Now we can substitute the given values into the equation for convective heat transfer:
Q = (1000)(0.314)(200 - 75)
Q = 31400 W
Therefore, the rate of heat transfer from the fuel rod to the water is 31400 W.
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Heat is being transferred convectively flow through a cylindrical nuclear reactor fuel rod of 50 mm diameter to water at 75°C. Under steady state condition, the rate of heat generation within the fuel element is 5 x107W/m3 and the. convection heat transfer coefficient is 1 kW/m2 K. The outer surface temperature of the fuel element would bea)700°Cb)625°Cc)550°Cd)400°CCorrect answer is option 'A'. Can you explain this answer?
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Heat is being transferred convectively flow through a cylindrical nuclear reactor fuel rod of 50 mm diameter to water at 75°C. Under steady state condition, the rate of heat generation within the fuel element is 5 x107W/m3 and the. convection heat transfer coefficient is 1 kW/m2 K. The outer surface temperature of the fuel element would bea)700°Cb)625°Cc)550°Cd)400°CCorrect answer is option 'A'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Heat is being transferred convectively flow through a cylindrical nuclear reactor fuel rod of 50 mm diameter to water at 75°C. Under steady state condition, the rate of heat generation within the fuel element is 5 x107W/m3 and the. convection heat transfer coefficient is 1 kW/m2 K. The outer surface temperature of the fuel element would bea)700°Cb)625°Cc)550°Cd)400°CCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Heat is being transferred convectively flow through a cylindrical nuclear reactor fuel rod of 50 mm diameter to water at 75°C. Under steady state condition, the rate of heat generation within the fuel element is 5 x107W/m3 and the. convection heat transfer coefficient is 1 kW/m2 K. The outer surface temperature of the fuel element would bea)700°Cb)625°Cc)550°Cd)400°CCorrect answer is option 'A'. Can you explain this answer?.
Heat is being transferred convectively flow through a cylindrical nuclear reactor fuel rod of 50 mm diameter to water at 75°C. Under steady state condition, the rate of heat generation within the fuel element is 5 x107W/m3 and the. convection heat transfer coefficient is 1 kW/m2 K. The outer surface temperature of the fuel element would bea)700°Cb)625°Cc)550°Cd)400°CCorrect answer is option 'A'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Heat is being transferred convectively flow through a cylindrical nuclear reactor fuel rod of 50 mm diameter to water at 75°C. Under steady state condition, the rate of heat generation within the fuel element is 5 x107W/m3 and the. convection heat transfer coefficient is 1 kW/m2 K. The outer surface temperature of the fuel element would bea)700°Cb)625°Cc)550°Cd)400°CCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Heat is being transferred convectively flow through a cylindrical nuclear reactor fuel rod of 50 mm diameter to water at 75°C. Under steady state condition, the rate of heat generation within the fuel element is 5 x107W/m3 and the. convection heat transfer coefficient is 1 kW/m2 K. The outer surface temperature of the fuel element would bea)700°Cb)625°Cc)550°Cd)400°CCorrect answer is option 'A'. Can you explain this answer?.
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