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A flat plate has thickness 5 cm, thermal conductivity 1 W/(mK) convective heat transfer coefficients on its two flat faces of 10 W/(m2K) and 20W/(m2K). The overall heat transfer coefficient for such a flat plate is
- a)5 W/(m2K)
- b)6.33 W/(m2K)
- c)20 W/(m2K)
- d)30 W/(m2K)
Correct answer is option 'A'. Can you explain this answer?
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Overall Heat Transfer Coefficient Formula:
The overall heat transfer coefficient (U) for a flat plate can be calculated using the following formula:
1/U = (1/h1) + (δ/k) + (1/h2)
Where:
U is the overall heat transfer coefficient
h1 is the convective heat transfer coefficient on the first face
h2 is the convective heat transfer coefficient on the second face
δ is the thickness of the plate
k is the thermal conductivity of the plate material
Given Data:
h1 = 10 W/(m^2K)
h2 = 20 W/(m^2K)
δ = 5 cm = 0.05 m
k = 1 W/(mK)
Calculation:
Substituting the given values into the formula, we get:
1/U = (1/10) + (0.05/1) + (1/20)
Simplifying the equation:
1/U = 0.1 + 0.05 + 0.05
1/U = 0.2
U = 1/(0.2)
U = 5 W/(m^2K)
Answer:
Therefore, the overall heat transfer coefficient for the flat plate is 5 W/(m^2K).
Explanation:
The overall heat transfer coefficient represents the combined effect of conduction and convection in transferring heat through a flat plate. It is the reciprocal of the sum of the individual thermal resistances of convection, conduction, and convection on the two faces of the plate.
In this case, the convective heat transfer coefficients on the two faces of the plate are given as 10 W/(m^2K) and 20 W/(m^2K) respectively. The thermal conductivity of the plate material is given as 1 W/(mK), and the thickness of the plate is given as 5 cm.
Using the formula for the overall heat transfer coefficient, we substitute the given values and calculate the reciprocal of the sum of the individual thermal resistances. Simplifying the equation gives us the overall heat transfer coefficient of 5 W/(m^2K).
This means that for every square meter of the plate's surface area, a temperature difference of 1 K will result in a heat transfer rate of 5 Watts. The higher the overall heat transfer coefficient, the more effective the plate is in transferring heat. In this case, the plate has a relatively high overall heat transfer coefficient, indicating efficient heat transfer through the plate.
The overall heat transfer coefficient (U) for a flat plate can be calculated using the following formula:
1/U = (1/h1) + (δ/k) + (1/h2)
Where:
U is the overall heat transfer coefficient
h1 is the convective heat transfer coefficient on the first face
h2 is the convective heat transfer coefficient on the second face
δ is the thickness of the plate
k is the thermal conductivity of the plate material
Given Data:
h1 = 10 W/(m^2K)
h2 = 20 W/(m^2K)
δ = 5 cm = 0.05 m
k = 1 W/(mK)
Calculation:
Substituting the given values into the formula, we get:
1/U = (1/10) + (0.05/1) + (1/20)
Simplifying the equation:
1/U = 0.1 + 0.05 + 0.05
1/U = 0.2
U = 1/(0.2)
U = 5 W/(m^2K)
Answer:
Therefore, the overall heat transfer coefficient for the flat plate is 5 W/(m^2K).
Explanation:
The overall heat transfer coefficient represents the combined effect of conduction and convection in transferring heat through a flat plate. It is the reciprocal of the sum of the individual thermal resistances of convection, conduction, and convection on the two faces of the plate.
In this case, the convective heat transfer coefficients on the two faces of the plate are given as 10 W/(m^2K) and 20 W/(m^2K) respectively. The thermal conductivity of the plate material is given as 1 W/(mK), and the thickness of the plate is given as 5 cm.
Using the formula for the overall heat transfer coefficient, we substitute the given values and calculate the reciprocal of the sum of the individual thermal resistances. Simplifying the equation gives us the overall heat transfer coefficient of 5 W/(m^2K).
This means that for every square meter of the plate's surface area, a temperature difference of 1 K will result in a heat transfer rate of 5 Watts. The higher the overall heat transfer coefficient, the more effective the plate is in transferring heat. In this case, the plate has a relatively high overall heat transfer coefficient, indicating efficient heat transfer through the plate.
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A flat plate has thickness 5 cm, thermal conductivity 1 W/(mK) convective heat transfer coefficients on its two flat faces of 10 W/(m2K) and 20W/(m2K). The overall heat transfer coefficient for such a flat plate isa)5 W/(m2K) b)6.33 W/(m2K)c)20 W/(m2K) d)30 W/(m2K)Correct answer is option 'A'. Can you explain this answer?
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A flat plate has thickness 5 cm, thermal conductivity 1 W/(mK) convective heat transfer coefficients on its two flat faces of 10 W/(m2K) and 20W/(m2K). The overall heat transfer coefficient for such a flat plate isa)5 W/(m2K) b)6.33 W/(m2K)c)20 W/(m2K) d)30 W/(m2K)Correct answer is option 'A'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A flat plate has thickness 5 cm, thermal conductivity 1 W/(mK) convective heat transfer coefficients on its two flat faces of 10 W/(m2K) and 20W/(m2K). The overall heat transfer coefficient for such a flat plate isa)5 W/(m2K) b)6.33 W/(m2K)c)20 W/(m2K) d)30 W/(m2K)Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A flat plate has thickness 5 cm, thermal conductivity 1 W/(mK) convective heat transfer coefficients on its two flat faces of 10 W/(m2K) and 20W/(m2K). The overall heat transfer coefficient for such a flat plate isa)5 W/(m2K) b)6.33 W/(m2K)c)20 W/(m2K) d)30 W/(m2K)Correct answer is option 'A'. Can you explain this answer?.
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