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One of the lines in the emission spectrum of Li2+ has the same wavelength as that of the 2nd line of Balmer series in hydrogen spectrum. The electronic transition corresponding to this line is :
  • a)
    n = 4 → n = 2
  • b)
    n = 8 → n = 2
  • c)
    n = 8 → n = 4
  • d)
    n = 12 → n = 6
Correct answer is option 'D'. Can you explain this answer?
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The Balmer series in the hydrogen spectrum is given by:

1/λ = R_H * (1/4 - 1/n^2)

where λ is the wavelength, R_H is the Rydberg constant for hydrogen, and n is the principal quantum number.

The 2nd line of the Balmer series corresponds to n = 4. Therefore, the wavelength of this line is:

1/λ = R_H * (1/4 - 1/4^2)
= R_H * (1/4 - 1/16)
= R_H * (3/16)

Now, we are told that one of the lines in the emission spectrum of Li2 has the same wavelength as this line. This means that the electronic transition in Li2 corresponds to n = 4 as well. Therefore, the answer is:

a) n = 4
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One of the lines in the emission spectrum of Li2+ has the same wavelength as that of the 2nd line of Balmer series in hydrogen spectrum. The electronic transition corresponding to this line is :a)n = 4 →n = 2b)n = 8 →n = 2c)n = 8 →n = 4d)n = 12 →n = 6Correct answer is option 'D'. Can you explain this answer?
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One of the lines in the emission spectrum of Li2+ has the same wavelength as that of the 2nd line of Balmer series in hydrogen spectrum. The electronic transition corresponding to this line is :a)n = 4 →n = 2b)n = 8 →n = 2c)n = 8 →n = 4d)n = 12 →n = 6Correct answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about One of the lines in the emission spectrum of Li2+ has the same wavelength as that of the 2nd line of Balmer series in hydrogen spectrum. The electronic transition corresponding to this line is :a)n = 4 →n = 2b)n = 8 →n = 2c)n = 8 →n = 4d)n = 12 →n = 6Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for One of the lines in the emission spectrum of Li2+ has the same wavelength as that of the 2nd line of Balmer series in hydrogen spectrum. The electronic transition corresponding to this line is :a)n = 4 →n = 2b)n = 8 →n = 2c)n = 8 →n = 4d)n = 12 →n = 6Correct answer is option 'D'. Can you explain this answer?.
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