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The decomposition of ammonia on molybdenum surface follows langumir hinshelwood mechanism. The decomposition was carried out at a low pressure . The intial pressure of ammonia was 10^-2 torr. The pressure of ammonia was reduced to 10^-4 torr in 10 min then the rate of decomposition is?
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Langmuir Hinshelwood Mechanism for Ammonia Decomposition on Molybdenum Surface
Ammonia decomposition on molybdenum surface follows Langmuir Hinshelwood mechanism, which involves the adsorption of reactants on the surface and subsequent reaction. The reaction can be represented as:
NH3(g) → 1/2N2(g) + 3/2H2(g)
Low Pressure Decomposition
The decomposition of ammonia was carried out at low pressure, where the initial pressure of ammonia was 10^-2 torr. The pressure of ammonia was reduced to 10^-4 torr in 10 minutes.
Rate of Decomposition
The rate of decomposition can be determined using the following formula:
Rate = -1/2 (d[P(N2)]/dt) = -3/2 (d[P(H2)]/dt)
Where [P(N2)] and [P(H2)] are the partial pressures of nitrogen and hydrogen, respectively.
Using the given initial and final pressures of ammonia, we can calculate the partial pressures of nitrogen and hydrogen at the end of the reaction. Assuming that the volume of the system remains constant, we can use the ideal gas law to calculate the number of moles of each species present:
PV = nRT
n(N2) = (P(N2)/RT)V
n(H2) = (P(H2)/RT)V
Substituting the values, we get:
n(N2) = 1.17 × 10^-5 mol
n(H2) = 3.51 × 10^-5 mol
Using the balanced chemical equation, we can relate the rate of decomposition to the rate of nitrogen and hydrogen production:
Rate = -1/2 (d[P(N2)]/dt) = -3/2 (d[P(H2)]/dt) = 1/3 (d[P(NH3)]/dt)
Therefore, the rate of decomposition can be calculated as:
Rate = (1/3) × (10^-2 - 10^-4)/10 = 0.00333 torr/min
Conclusion
The rate of decomposition of ammonia on molybdenum surface can be determined using the Langmuir Hinshelwood mechanism and the partial pressures of nitrogen and hydrogen produced. The low pressure conditions ensure that the reaction follows the Langmuir Hinshelwood mechanism, and the rate of decomposition can be calculated using the ideal gas law and the balanced chemical equation.
Ammonia decomposition on molybdenum surface follows Langmuir Hinshelwood mechanism, which involves the adsorption of reactants on the surface and subsequent reaction. The reaction can be represented as:
NH3(g) → 1/2N2(g) + 3/2H2(g)
Low Pressure Decomposition
The decomposition of ammonia was carried out at low pressure, where the initial pressure of ammonia was 10^-2 torr. The pressure of ammonia was reduced to 10^-4 torr in 10 minutes.
Rate of Decomposition
The rate of decomposition can be determined using the following formula:
Rate = -1/2 (d[P(N2)]/dt) = -3/2 (d[P(H2)]/dt)
Where [P(N2)] and [P(H2)] are the partial pressures of nitrogen and hydrogen, respectively.
Using the given initial and final pressures of ammonia, we can calculate the partial pressures of nitrogen and hydrogen at the end of the reaction. Assuming that the volume of the system remains constant, we can use the ideal gas law to calculate the number of moles of each species present:
PV = nRT
n(N2) = (P(N2)/RT)V
n(H2) = (P(H2)/RT)V
Substituting the values, we get:
n(N2) = 1.17 × 10^-5 mol
n(H2) = 3.51 × 10^-5 mol
Using the balanced chemical equation, we can relate the rate of decomposition to the rate of nitrogen and hydrogen production:
Rate = -1/2 (d[P(N2)]/dt) = -3/2 (d[P(H2)]/dt) = 1/3 (d[P(NH3)]/dt)
Therefore, the rate of decomposition can be calculated as:
Rate = (1/3) × (10^-2 - 10^-4)/10 = 0.00333 torr/min
Conclusion
The rate of decomposition of ammonia on molybdenum surface can be determined using the Langmuir Hinshelwood mechanism and the partial pressures of nitrogen and hydrogen produced. The low pressure conditions ensure that the reaction follows the Langmuir Hinshelwood mechanism, and the rate of decomposition can be calculated using the ideal gas law and the balanced chemical equation.
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The decomposition of ammonia on molybdenum surface follows langumir hinshelwood mechanism. The decomposition was carried out at a low pressure . The intial pressure of ammonia was 10^-2 torr. The pressure of ammonia was reduced to 10^-4 torr in 10 min then the rate of decomposition is?
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The decomposition of ammonia on molybdenum surface follows langumir hinshelwood mechanism. The decomposition was carried out at a low pressure . The intial pressure of ammonia was 10^-2 torr. The pressure of ammonia was reduced to 10^-4 torr in 10 min then the rate of decomposition is? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about The decomposition of ammonia on molybdenum surface follows langumir hinshelwood mechanism. The decomposition was carried out at a low pressure . The intial pressure of ammonia was 10^-2 torr. The pressure of ammonia was reduced to 10^-4 torr in 10 min then the rate of decomposition is? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The decomposition of ammonia on molybdenum surface follows langumir hinshelwood mechanism. The decomposition was carried out at a low pressure . The intial pressure of ammonia was 10^-2 torr. The pressure of ammonia was reduced to 10^-4 torr in 10 min then the rate of decomposition is?.
The decomposition of ammonia on molybdenum surface follows langumir hinshelwood mechanism. The decomposition was carried out at a low pressure . The intial pressure of ammonia was 10^-2 torr. The pressure of ammonia was reduced to 10^-4 torr in 10 min then the rate of decomposition is? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about The decomposition of ammonia on molybdenum surface follows langumir hinshelwood mechanism. The decomposition was carried out at a low pressure . The intial pressure of ammonia was 10^-2 torr. The pressure of ammonia was reduced to 10^-4 torr in 10 min then the rate of decomposition is? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The decomposition of ammonia on molybdenum surface follows langumir hinshelwood mechanism. The decomposition was carried out at a low pressure . The intial pressure of ammonia was 10^-2 torr. The pressure of ammonia was reduced to 10^-4 torr in 10 min then the rate of decomposition is?.
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