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Consider two subsystem 1 and 2 containing same fluid and having same mass m; but at Temperature T1 and T2(T> T2) enclosed in an adiabatic enclosure separate by a partition, if the partition is removed and the fluids are allowed to mix. The entropy change of process is
  • a)
  • b)
  • c)
  • d)
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Consider two subsystem 1 and 2 containing same fluid and having same m...
Subsystem 1 having a fluid of mass m1 specific heat c1 and temperature t1 and subsystem 2 consisting of a fluid of mass m2, specific heat c2, and temperature t2, comprise a composite system in an adiabatic enclosure figure. When the partition is removed, the two fluids mix together, and at equilibrium let tf be the final temperature, and t2 < tf < t1 Since energy interaction is exclusively confined to the two fluids, the system being isolated

∴  

Entropy change for the fluid in subsystem1,

This will be negative, since T> Tf
Entropy change for the fluid in subsystem 2

This will be positive, since T2 < Tf

ΔSuniv will be positive definite, and the mixing process is irreversible.
Although the mixing process is irreversible, to evaluate the entropy change for the subsystem, the irreversible path was replaced by a reversible path on which the integration was performed.

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