Consider two subsystem 1 and 2 containing same fluid and having same mass m; but at Temperature T1 and T2(T1andgt; T2) enclosed in an adiabatic enclosure separate by a partition, if the partition is removed and the fluids are allowed to mix. The entropy change of process isa)b)c)d)Correct answer is option 'B'. Can you explain this answer?

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Consider two subsystem 1 and 2 containing same fluid and having same mass m; but at Temperature T₁ and T₂(T₁> T₂) enclosed in an adiabatic enclosure separate by a partition, if the partition is removed and the fluids are allowed to mix. The entropy change of process is

Correct answer is option 'B'. Can you explain this answer?

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Consider two subsystem 1 and 2 containing same fluid and having same m...

Subsystem 1 having a fluid of mass m₁ specific heat c₁ and temperature t₁ and subsystem 2 consisting of a fluid of mass m₂, specific heat c₂, and temperature t₂, comprise a composite system in an adiabatic enclosure figure. When the partition is removed, the two fluids mix together, and at equilibrium let t_fbe the final temperature, and t₂ < t_f < t₁ Since energy interaction is exclusively confined to the two fluids, the system being isolated

∴

Entropy change for the fluid in subsystem1,

This will be negative, since T₁> T_f
Entropy change for the fluid in subsystem 2

This will be positive, since T₂ < T_f
ΔS_univ will be positive definite, and the mixing process is irreversible.
Although the mixing process is irreversible, to evaluate the entropy change for the subsystem, the irreversible path was replaced by a reversible path on which the integration was performed.

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Consider two subsystem 1 and 2 containing same fluid and having same mass m; but at Temperature T1 and T2(T1> T2) enclosed in an adiabatic enclosure separate by a partition, if the partition is removed and the fluids are allowed to mix. The entropy change of process isa)b)c)d)Correct answer is option 'B'. Can you explain this answer?

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