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(Ans. 1 Three marks A, B, C, spaced at a distance of 100 m are made along a straish starting from rest and accelerating uniformly passes the mark A and takes 10 s the mark B and further 8 seconds to reach mark C. Calculate: (a) the magnitude of the acceleration of the car; (b) the velocity of the car at A; (c) the velocity of the car at B; and (d) the distance of the mark A fror. [Ans . (a) 0.2?
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(Ans. 1 Three marks A, B, C, spaced at a distance of 100 m are made al...
Calculation of Acceleration, Velocity and Distance of a Car
Given Data:
Distance between A, B and C marks = 100 m
Time taken to reach mark B from A = 10 s
Time taken to reach mark C from B = 8 s
(a) Calculation of Acceleration:
Acceleration is the rate of change of velocity with respect to time. It can be calculated using the following formula:
a = (v2 - v1) / t
where,
v1 = initial velocity
v2 = final velocity
t = time taken
Here, the car starts from rest, hence the initial velocity (v1) is 0 m/s.
The time taken to reach mark B from A is 10 s and the distance covered is 100 m, hence the final velocity (v2) at mark B can be calculated using the formula:
v2 = (2*s) / t
where, s = distance covered
v2 = (2*100) / 10 = 20 m/s
Similarly, the final velocity (v3) at mark C can be calculated using the formula:
v3 = (2*s) / t
where, s = distance covered
v3 = (2*100) / 8 = 25 m/s
Now, using the acceleration formula, we can calculate the acceleration (a) of the car as:
a = (v2 - v1) / t = (20 - 0) / 10 = 2 m/s^2
Hence, the magnitude of the acceleration of the car is 2 m/s^2.
(b) Calculation of Velocity at A:
As the car starts from rest, the initial velocity (v1) at mark A is 0 m/s.
(c) Calculation of Velocity at B:
The final velocity (v2) at mark B is 20 m/s, as calculated earlier.
(d) Calculation of Distance of Mark A:
As the distance between A, B and C marks is 100 m each, the distance of mark A from the start point is 0 m.
Therefore, the acceleration of the car is 2 m/s^2, the velocity of the car at A is 0 m/s, the velocity of the car at B is 20 m/s and the distance of mark A from the start point is 0 m.
Given Data:
Distance between A, B and C marks = 100 m
Time taken to reach mark B from A = 10 s
Time taken to reach mark C from B = 8 s
(a) Calculation of Acceleration:
Acceleration is the rate of change of velocity with respect to time. It can be calculated using the following formula:
a = (v2 - v1) / t
where,
v1 = initial velocity
v2 = final velocity
t = time taken
Here, the car starts from rest, hence the initial velocity (v1) is 0 m/s.
The time taken to reach mark B from A is 10 s and the distance covered is 100 m, hence the final velocity (v2) at mark B can be calculated using the formula:
v2 = (2*s) / t
where, s = distance covered
v2 = (2*100) / 10 = 20 m/s
Similarly, the final velocity (v3) at mark C can be calculated using the formula:
v3 = (2*s) / t
where, s = distance covered
v3 = (2*100) / 8 = 25 m/s
Now, using the acceleration formula, we can calculate the acceleration (a) of the car as:
a = (v2 - v1) / t = (20 - 0) / 10 = 2 m/s^2
Hence, the magnitude of the acceleration of the car is 2 m/s^2.
(b) Calculation of Velocity at A:
As the car starts from rest, the initial velocity (v1) at mark A is 0 m/s.
(c) Calculation of Velocity at B:
The final velocity (v2) at mark B is 20 m/s, as calculated earlier.
(d) Calculation of Distance of Mark A:
As the distance between A, B and C marks is 100 m each, the distance of mark A from the start point is 0 m.
Therefore, the acceleration of the car is 2 m/s^2, the velocity of the car at A is 0 m/s, the velocity of the car at B is 20 m/s and the distance of mark A from the start point is 0 m.
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(Ans. 1 Three marks A, B, C, spaced at a distance of 100 m are made along a straish starting from rest and accelerating uniformly passes the mark A and takes 10 s the mark B and further 8 seconds to reach mark C. Calculate: (a) the magnitude of the acceleration of the car; (b) the velocity of the car at A; (c) the velocity of the car at B; and (d) the distance of the mark A fror. [Ans . (a) 0.2?
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(Ans. 1 Three marks A, B, C, spaced at a distance of 100 m are made along a straish starting from rest and accelerating uniformly passes the mark A and takes 10 s the mark B and further 8 seconds to reach mark C. Calculate: (a) the magnitude of the acceleration of the car; (b) the velocity of the car at A; (c) the velocity of the car at B; and (d) the distance of the mark A fror. [Ans . (a) 0.2? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about (Ans. 1 Three marks A, B, C, spaced at a distance of 100 m are made along a straish starting from rest and accelerating uniformly passes the mark A and takes 10 s the mark B and further 8 seconds to reach mark C. Calculate: (a) the magnitude of the acceleration of the car; (b) the velocity of the car at A; (c) the velocity of the car at B; and (d) the distance of the mark A fror. [Ans . (a) 0.2? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for (Ans. 1 Three marks A, B, C, spaced at a distance of 100 m are made along a straish starting from rest and accelerating uniformly passes the mark A and takes 10 s the mark B and further 8 seconds to reach mark C. Calculate: (a) the magnitude of the acceleration of the car; (b) the velocity of the car at A; (c) the velocity of the car at B; and (d) the distance of the mark A fror. [Ans . (a) 0.2?.
(Ans. 1 Three marks A, B, C, spaced at a distance of 100 m are made along a straish starting from rest and accelerating uniformly passes the mark A and takes 10 s the mark B and further 8 seconds to reach mark C. Calculate: (a) the magnitude of the acceleration of the car; (b) the velocity of the car at A; (c) the velocity of the car at B; and (d) the distance of the mark A fror. [Ans . (a) 0.2? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about (Ans. 1 Three marks A, B, C, spaced at a distance of 100 m are made along a straish starting from rest and accelerating uniformly passes the mark A and takes 10 s the mark B and further 8 seconds to reach mark C. Calculate: (a) the magnitude of the acceleration of the car; (b) the velocity of the car at A; (c) the velocity of the car at B; and (d) the distance of the mark A fror. [Ans . (a) 0.2? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for (Ans. 1 Three marks A, B, C, spaced at a distance of 100 m are made along a straish starting from rest and accelerating uniformly passes the mark A and takes 10 s the mark B and further 8 seconds to reach mark C. Calculate: (a) the magnitude of the acceleration of the car; (b) the velocity of the car at A; (c) the velocity of the car at B; and (d) the distance of the mark A fror. [Ans . (a) 0.2?.
Solutions for (Ans. 1 Three marks A, B, C, spaced at a distance of 100 m are made along a straish starting from rest and accelerating uniformly passes the mark A and takes 10 s the mark B and further 8 seconds to reach mark C. Calculate: (a) the magnitude of the acceleration of the car; (b) the velocity of the car at A; (c) the velocity of the car at B; and (d) the distance of the mark A fror. [Ans . (a) 0.2? in English & in Hindi are available as part of our courses for Mechanical Engineering.
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