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A knuckle joint carries 150KN load with permissible stresses in 75MPa in tension ,60MPa in shear and 150Mpa in crushing Find Diameter of Rod. 45mm 60mm 65mm 51mm?
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A knuckle joint carries 150KN load with permissible stresses in 75MPa ...
Problem Statement: Find the diameter of the rod for a knuckle joint that carries a load of 150KN with permissible stresses of 75MPa in tension, 60MPa in shear, and 150Mpa in crushing.
Solution:
To find the diameter of the rod, we need to calculate the stresses in tension, shear, and crushing using the load and permissible stresses. Once we have the stresses, we can use the formula for stress in tension, shear, and crushing to solve for the diameter of the rod.
Stresses Calculation:
Let's calculate the stresses one by one.
Tensile stress = 150000/πd^2/4
Using the permissible stress of 75MPa, we can write the equation as:
75 = 150000/πd^2/4
d = √(4x150000/πx75) = 51mm
Shear stress = 150000/πd^3/32
Using the permissible stress of 60MPa, we can write the equation as:
60 = 150000/πd^3/32
d = ∛(32x150000/πx60) = 45mm
Crushing stress = 150000/πd^2/4
Using the permissible stress of 150MPa, we can write the equation as:
150 = 150000/πd^2/4
d = √(4x150000/πx150) = 60mm
Conclusion:
From the calculations, we can see that the diameter of the rod is different for each type of stress. The diameter of the rod is 51mm for tensile stress, 45mm for shear stress, and 60mm for crushing stress. Since the diameter of the rod should be selected based on the maximum stress, we can select the diameter of the rod as 51mm as it is the minimum of all three.
Solution:
To find the diameter of the rod, we need to calculate the stresses in tension, shear, and crushing using the load and permissible stresses. Once we have the stresses, we can use the formula for stress in tension, shear, and crushing to solve for the diameter of the rod.
Stresses Calculation:
- Tensile stress = Load/Area
- Shear stress = Load/Area
- Crushing stress = Load/Area
Let's calculate the stresses one by one.
Tensile stress = 150000/πd^2/4
Using the permissible stress of 75MPa, we can write the equation as:
75 = 150000/πd^2/4
d = √(4x150000/πx75) = 51mm
Shear stress = 150000/πd^3/32
Using the permissible stress of 60MPa, we can write the equation as:
60 = 150000/πd^3/32
d = ∛(32x150000/πx60) = 45mm
Crushing stress = 150000/πd^2/4
Using the permissible stress of 150MPa, we can write the equation as:
150 = 150000/πd^2/4
d = √(4x150000/πx150) = 60mm
Conclusion:
From the calculations, we can see that the diameter of the rod is different for each type of stress. The diameter of the rod is 51mm for tensile stress, 45mm for shear stress, and 60mm for crushing stress. Since the diameter of the rod should be selected based on the maximum stress, we can select the diameter of the rod as 51mm as it is the minimum of all three.
Community Answer
A knuckle joint carries 150KN load with permissible stresses in 75MPa ...
50.46mm
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A knuckle joint carries 150KN load with permissible stresses in 75MPa in tension ,60MPa in shear and 150Mpa in crushing Find Diameter of Rod. 45mm 60mm 65mm 51mm?
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A knuckle joint carries 150KN load with permissible stresses in 75MPa in tension ,60MPa in shear and 150Mpa in crushing Find Diameter of Rod. 45mm 60mm 65mm 51mm? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A knuckle joint carries 150KN load with permissible stresses in 75MPa in tension ,60MPa in shear and 150Mpa in crushing Find Diameter of Rod. 45mm 60mm 65mm 51mm? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A knuckle joint carries 150KN load with permissible stresses in 75MPa in tension ,60MPa in shear and 150Mpa in crushing Find Diameter of Rod. 45mm 60mm 65mm 51mm?.
A knuckle joint carries 150KN load with permissible stresses in 75MPa in tension ,60MPa in shear and 150Mpa in crushing Find Diameter of Rod. 45mm 60mm 65mm 51mm? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A knuckle joint carries 150KN load with permissible stresses in 75MPa in tension ,60MPa in shear and 150Mpa in crushing Find Diameter of Rod. 45mm 60mm 65mm 51mm? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A knuckle joint carries 150KN load with permissible stresses in 75MPa in tension ,60MPa in shear and 150Mpa in crushing Find Diameter of Rod. 45mm 60mm 65mm 51mm?.
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