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In a cyclic Quadrlateral ABCD, angle B = (x+50) and angle D = (x+10), then the value of x is?
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In a cyclic Quadrlateral ABCD, angle B = (x+50) and angle D = (x+10), ...
In cyclic quadrilateral sum of opposite angle is 180*

Angle D + Angle B = 180*
(X + 10) + (X+ 50)=. 180*
2x. +60. =. 180*
2x. =. 180* -- 60*
X. =. 120/2
X. =. 60*
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In a cyclic Quadrlateral ABCD, angle B = (x+50) and angle D = (x+10), then the value of x is?
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