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A ricket of 3*10 to the power of 6 kg mass takes off from a launching pad and acquires a vertical velocity of 1km/s at an altitude of 25 km. Calculate(a) the potential energy (b) the kinetic energy.( Take the value of g =10 m/ s) ? pliz koi bta do.
Verified Answer
A ricket of 3*10 to the power of 6 kg mass takes off from a launching ...
Mass of the Rocket,m = 3 * 10^6 kg
Velocity = 1 km/s = 1000 m/s
Altitude,h= 25 km = 25 * 1000m
=25000m
(a)Potential Energy=mgh
=3 * 10^6 * 10 * 25000
= 75 * 10^10 Joule
(b) Kinetic Energy = 1/2 mv^2
=1/2 * 3 * 10^6 * (1000)^2
= 1.5 * 10^12 Joule
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Most Upvoted Answer
A ricket of 3*10 to the power of 6 kg mass takes off from a launching ...
Potential Energy
The potential energy of an object is the energy that it possesses due to its position relative to other objects. In this case, the rocket has a mass of 3*10^6 kg and is at an altitude of 25 km.
The potential energy of an object near the surface of the Earth can be calculated using the formula:
Potential Energy = mass * acceleration due to gravity * height
Given that the mass of the rocket is 3*10^6 kg and the acceleration due to gravity is 10 m/s^2, and the height is 25 km (which is equivalent to 25,000 m), we can calculate the potential energy as follows:
Potential Energy = 3*10^6 kg * 10 m/s^2 * 25,000 m
Calculating this expression, we get:
Potential Energy = 7.5 * 10^11 J
Therefore, the potential energy of the rocket is 7.5 * 10^11 Joules.
Kinetic Energy
The kinetic energy of an object is the energy that it possesses due to its motion. In this case, the rocket has a vertical velocity of 1 km/s.
The kinetic energy of an object can be calculated using the formula:
Kinetic Energy = (1/2) * mass * velocity^2
Given that the mass of the rocket is 3*10^6 kg and the velocity is 1 km/s (which is equivalent to 1000 m/s), we can calculate the kinetic energy as follows:
Kinetic Energy = (1/2) * 3*10^6 kg * (1000 m/s)^2
Simplifying this expression, we get:
Kinetic Energy = 1.5 * 10^12 J
Therefore, the kinetic energy of the rocket is 1.5 * 10^12 Joules.
Summary
To summarize, the potential energy of the rocket is 7.5 * 10^11 Joules and the kinetic energy is 1.5 * 10^12 Joules.
The potential energy of an object is the energy that it possesses due to its position relative to other objects. In this case, the rocket has a mass of 3*10^6 kg and is at an altitude of 25 km.
The potential energy of an object near the surface of the Earth can be calculated using the formula:
Potential Energy = mass * acceleration due to gravity * height
Given that the mass of the rocket is 3*10^6 kg and the acceleration due to gravity is 10 m/s^2, and the height is 25 km (which is equivalent to 25,000 m), we can calculate the potential energy as follows:
Potential Energy = 3*10^6 kg * 10 m/s^2 * 25,000 m
Calculating this expression, we get:
Potential Energy = 7.5 * 10^11 J
Therefore, the potential energy of the rocket is 7.5 * 10^11 Joules.
Kinetic Energy
The kinetic energy of an object is the energy that it possesses due to its motion. In this case, the rocket has a vertical velocity of 1 km/s.
The kinetic energy of an object can be calculated using the formula:
Kinetic Energy = (1/2) * mass * velocity^2
Given that the mass of the rocket is 3*10^6 kg and the velocity is 1 km/s (which is equivalent to 1000 m/s), we can calculate the kinetic energy as follows:
Kinetic Energy = (1/2) * 3*10^6 kg * (1000 m/s)^2
Simplifying this expression, we get:
Kinetic Energy = 1.5 * 10^12 J
Therefore, the kinetic energy of the rocket is 1.5 * 10^12 Joules.
Summary
To summarize, the potential energy of the rocket is 7.5 * 10^11 Joules and the kinetic energy is 1.5 * 10^12 Joules.
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A ricket of 3*10 to the power of 6 kg mass takes off from a launching pad and acquires a vertical velocity of 1km/s at an altitude of 25 km. Calculate(a) the potential energy (b) the kinetic energy.( Take the value of g =10 m/ s) ? pliz koi bta do.
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A ricket of 3*10 to the power of 6 kg mass takes off from a launching pad and acquires a vertical velocity of 1km/s at an altitude of 25 km. Calculate(a) the potential energy (b) the kinetic energy.( Take the value of g =10 m/ s) ? pliz koi bta do. for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A ricket of 3*10 to the power of 6 kg mass takes off from a launching pad and acquires a vertical velocity of 1km/s at an altitude of 25 km. Calculate(a) the potential energy (b) the kinetic energy.( Take the value of g =10 m/ s) ? pliz koi bta do. covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A ricket of 3*10 to the power of 6 kg mass takes off from a launching pad and acquires a vertical velocity of 1km/s at an altitude of 25 km. Calculate(a) the potential energy (b) the kinetic energy.( Take the value of g =10 m/ s) ? pliz koi bta do..
A ricket of 3*10 to the power of 6 kg mass takes off from a launching pad and acquires a vertical velocity of 1km/s at an altitude of 25 km. Calculate(a) the potential energy (b) the kinetic energy.( Take the value of g =10 m/ s) ? pliz koi bta do. for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A ricket of 3*10 to the power of 6 kg mass takes off from a launching pad and acquires a vertical velocity of 1km/s at an altitude of 25 km. Calculate(a) the potential energy (b) the kinetic energy.( Take the value of g =10 m/ s) ? pliz koi bta do. covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A ricket of 3*10 to the power of 6 kg mass takes off from a launching pad and acquires a vertical velocity of 1km/s at an altitude of 25 km. Calculate(a) the potential energy (b) the kinetic energy.( Take the value of g =10 m/ s) ? pliz koi bta do..
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