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In a class, 2/5TH of the students are girls and rest are boys. If 4/9 of the girls and 1/3 of the boys are absent. What part of the total number of students are present?
- a)28/45
- b)23/36
- c)18/49
- d)17/25
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
In a class, 2/5THof the students are girls and rest are boys. If 4/9 o...
Number of Girls = 2/5 of the class
Number of Girls (Absent) = 4/9
Number of Boys (Absent) = 1/3
FORMULA USED:
The total number of students who are present = Total number of students – Total number of Boys and Girls who are absent
CALCULATION:
Let the total number of students in a class be x
∴ According to the question,
Number of girls = 2/5 x and number of boys = x – 2/5 x = 3/5 x
Number of girls who are absent = 2/5 × 4/9 x = 8x/45 and number of boys who are absent = 3/5 × 1/3 x = x/5
Total number of students who are present = x – 8x/45 – x/5 = (45x – 8x – 9x)/45 = 28x/45
∴ The 28/45thpart of the students are present in the class
Most Upvoted Answer
In a class, 2/5THof the students are girls and rest are boys. If 4/9 o...
Given information:
- 2/5th of the students are girls
- The rest are boys
- 4/9 of the girls are absent
- 1/3 of the boys are absent
To find: The part of the total number of students that are present.
Let's assume the total number of students as 'x'.
Number of girls = 2/5 * x
Number of boys = x - (2/5 * x) = 3/5 * x
Now let's find the number of girls absent and boys absent.
Number of girls absent = 4/9 * (2/5 * x) = 8/45 * x
Number of boys absent = 1/3 * (3/5 * x) = 1/5 * x
The number of students present is given by:
Number of students present = Total number of students - Number of students absent
Plugging in the values:
Number of students present = x - (8/45 * x + 1/5 * x)
Number of students present = x - (8/45 + 1/5) * x
Number of students present = x - (40/225 + 45/225) * x
Number of students present = x - (85/225) * x
Number of students present = (225x - 85x) / 225
Number of students present = 140x / 225
Simplifying the fraction:
Number of students present = 28/45 * x
Therefore, the part of the total number of students that are present is 28/45, which corresponds to option 'A'.
- 2/5th of the students are girls
- The rest are boys
- 4/9 of the girls are absent
- 1/3 of the boys are absent
To find: The part of the total number of students that are present.
Let's assume the total number of students as 'x'.
Number of girls = 2/5 * x
Number of boys = x - (2/5 * x) = 3/5 * x
Now let's find the number of girls absent and boys absent.
Number of girls absent = 4/9 * (2/5 * x) = 8/45 * x
Number of boys absent = 1/3 * (3/5 * x) = 1/5 * x
The number of students present is given by:
Number of students present = Total number of students - Number of students absent
Plugging in the values:
Number of students present = x - (8/45 * x + 1/5 * x)
Number of students present = x - (8/45 + 1/5) * x
Number of students present = x - (40/225 + 45/225) * x
Number of students present = x - (85/225) * x
Number of students present = (225x - 85x) / 225
Number of students present = 140x / 225
Simplifying the fraction:
Number of students present = 28/45 * x
Therefore, the part of the total number of students that are present is 28/45, which corresponds to option 'A'.
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In a class, 2/5THof the students are girls and rest are boys. If 4/9 of the girls and 1/3 of the boys are absent. What part of the total number of students are present?a)28/45b)23/36c)18/49d)17/25Correct answer is option 'A'. Can you explain this answer?
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