Class 12 Exam > Class 12 Questions > a wire 40cm long is bent into a rectangular f...
Start Learning for Free
a wire 40cm long is bent into a rectangular frame 15cm and 5cm and placed perpendicular to a field of induction 0.8T .In 0.5sec ,the frame is changed into a square frame and the field is increased to 1.4T .Then e. m.f induced in the frame
Most Upvoted Answer
a wire 40cm long is bent into a rectangular frame 15cm and 5cm and pla...
Community Answer
a wire 40cm long is bent into a rectangular frame 15cm and 5cm and pla...
Initial Conditions:
- Length of the wire: 40 cm
- Dimensions of the rectangular frame: 15 cm x 5 cm
- Magnetic field induction: 0.8 T
Step 1: Calculating the initial area:
To calculate the initial area of the rectangular frame, we use the formula: Area = length x width.
Area = 15 cm x 5 cm = 75 cm².
Step 2: Calculating the initial magnetic flux:
The magnetic flux (Φ) through a loop is given by the formula: Φ = B x A, where B is the magnetic field induction and A is the area.
Initial magnetic flux (Φ₁) = 0.8 T x 75 cm² = 60 cm²·T.
Step 3: Changing the frame into a square:
In 0.5 sec, the rectangular frame is changed into a square frame. This means that the dimensions of the frame change to be equal.
Let the new side length of the square frame be 's' cm.
Step 4: Calculating the new area:
The new area of the square frame is given by the formula: Area = side length².
New area = s² cm².
Step 5: Calculating the new magnetic flux:
The magnetic flux through the square frame (Φ₂) is given by the formula: Φ₂ = B₂ x A₂, where B₂ is the new magnetic field induction and A₂ is the new area.
New magnetic flux (Φ₂) = 1.4 T x s² cm².
Step 6: Calculating the change in magnetic flux:
The change in magnetic flux (ΔΦ) is given by the formula: ΔΦ = Φ₂ - Φ₁.
ΔΦ = 1.4 T x s² cm² - 60 cm²·T.
Step 7: Calculating the induced electromotive force (emf):
The induced emf (ε) is given by Faraday's law: ε = -dΦ/dt, where dΦ/dt is the rate of change of magnetic flux.
Rate of change of magnetic flux = ΔΦ / Δt = (1.4 T x s² cm² - 60 cm²·T) / 0.5 sec.
Step 8: Simplifying the expression:
To simplify the expression, we convert the units to SI units.
1 cm = 0.01 m.
1 T = 1 Wb/m² = 1 V·s/m².
Final Answer:
The electromotive force induced in the frame can be calculated by substituting the values into the derived equation in Step 7 and simplifying the expression.
- Length of the wire: 40 cm
- Dimensions of the rectangular frame: 15 cm x 5 cm
- Magnetic field induction: 0.8 T
Step 1: Calculating the initial area:
To calculate the initial area of the rectangular frame, we use the formula: Area = length x width.
Area = 15 cm x 5 cm = 75 cm².
Step 2: Calculating the initial magnetic flux:
The magnetic flux (Φ) through a loop is given by the formula: Φ = B x A, where B is the magnetic field induction and A is the area.
Initial magnetic flux (Φ₁) = 0.8 T x 75 cm² = 60 cm²·T.
Step 3: Changing the frame into a square:
In 0.5 sec, the rectangular frame is changed into a square frame. This means that the dimensions of the frame change to be equal.
Let the new side length of the square frame be 's' cm.
Step 4: Calculating the new area:
The new area of the square frame is given by the formula: Area = side length².
New area = s² cm².
Step 5: Calculating the new magnetic flux:
The magnetic flux through the square frame (Φ₂) is given by the formula: Φ₂ = B₂ x A₂, where B₂ is the new magnetic field induction and A₂ is the new area.
New magnetic flux (Φ₂) = 1.4 T x s² cm².
Step 6: Calculating the change in magnetic flux:
The change in magnetic flux (ΔΦ) is given by the formula: ΔΦ = Φ₂ - Φ₁.
ΔΦ = 1.4 T x s² cm² - 60 cm²·T.
Step 7: Calculating the induced electromotive force (emf):
The induced emf (ε) is given by Faraday's law: ε = -dΦ/dt, where dΦ/dt is the rate of change of magnetic flux.
Rate of change of magnetic flux = ΔΦ / Δt = (1.4 T x s² cm² - 60 cm²·T) / 0.5 sec.
Step 8: Simplifying the expression:
To simplify the expression, we convert the units to SI units.
1 cm = 0.01 m.
1 T = 1 Wb/m² = 1 V·s/m².
Final Answer:
The electromotive force induced in the frame can be calculated by substituting the values into the derived equation in Step 7 and simplifying the expression.
|
Explore Courses for Class 12 exam
|
|
Similar Class 12 Doubts
a wire 40cm long is bent into a rectangular frame 15cm and 5cm and placed perpendicular to a field of induction 0.8T .In 0.5sec ,the frame is changed into a square frame and the field is increased to 1.4T .Then e. m.f induced in the frame
Question Description
a wire 40cm long is bent into a rectangular frame 15cm and 5cm and placed perpendicular to a field of induction 0.8T .In 0.5sec ,the frame is changed into a square frame and the field is increased to 1.4T .Then e. m.f induced in the frame for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about a wire 40cm long is bent into a rectangular frame 15cm and 5cm and placed perpendicular to a field of induction 0.8T .In 0.5sec ,the frame is changed into a square frame and the field is increased to 1.4T .Then e. m.f induced in the frame covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for a wire 40cm long is bent into a rectangular frame 15cm and 5cm and placed perpendicular to a field of induction 0.8T .In 0.5sec ,the frame is changed into a square frame and the field is increased to 1.4T .Then e. m.f induced in the frame.
a wire 40cm long is bent into a rectangular frame 15cm and 5cm and placed perpendicular to a field of induction 0.8T .In 0.5sec ,the frame is changed into a square frame and the field is increased to 1.4T .Then e. m.f induced in the frame for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about a wire 40cm long is bent into a rectangular frame 15cm and 5cm and placed perpendicular to a field of induction 0.8T .In 0.5sec ,the frame is changed into a square frame and the field is increased to 1.4T .Then e. m.f induced in the frame covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for a wire 40cm long is bent into a rectangular frame 15cm and 5cm and placed perpendicular to a field of induction 0.8T .In 0.5sec ,the frame is changed into a square frame and the field is increased to 1.4T .Then e. m.f induced in the frame.
Solutions for a wire 40cm long is bent into a rectangular frame 15cm and 5cm and placed perpendicular to a field of induction 0.8T .In 0.5sec ,the frame is changed into a square frame and the field is increased to 1.4T .Then e. m.f induced in the frame in English & in Hindi are available as part of our courses for Class 12.
Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.
Here you can find the meaning of a wire 40cm long is bent into a rectangular frame 15cm and 5cm and placed perpendicular to a field of induction 0.8T .In 0.5sec ,the frame is changed into a square frame and the field is increased to 1.4T .Then e. m.f induced in the frame defined & explained in the simplest way possible. Besides giving the explanation of
a wire 40cm long is bent into a rectangular frame 15cm and 5cm and placed perpendicular to a field of induction 0.8T .In 0.5sec ,the frame is changed into a square frame and the field is increased to 1.4T .Then e. m.f induced in the frame, a detailed solution for a wire 40cm long is bent into a rectangular frame 15cm and 5cm and placed perpendicular to a field of induction 0.8T .In 0.5sec ,the frame is changed into a square frame and the field is increased to 1.4T .Then e. m.f induced in the frame has been provided alongside types of a wire 40cm long is bent into a rectangular frame 15cm and 5cm and placed perpendicular to a field of induction 0.8T .In 0.5sec ,the frame is changed into a square frame and the field is increased to 1.4T .Then e. m.f induced in the frame theory, EduRev gives you an
ample number of questions to practice a wire 40cm long is bent into a rectangular frame 15cm and 5cm and placed perpendicular to a field of induction 0.8T .In 0.5sec ,the frame is changed into a square frame and the field is increased to 1.4T .Then e. m.f induced in the frame tests, examples and also practice Class 12 tests.
|
|
Explore Courses for Class 12 exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup