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Steel bar of 40 mm × 40 mm square cross section is subjected to an axial compressive load of 200 Newton if the length of the bar is 2 metre and C is equal to 200 Gamma Pascal solve from the the contraction of the bar will be?
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Steel bar of 40 mm × 40 mm square cross section is subjected to an axi...
Given Data:
- Cross-sectional area of the steel bar: 40 mm × 40 mm
- Axial compressive load: 200 Newton
- Length of the bar: 2 meters
- C (modulus of elasticity) = 200 GPa (giga Pascal)
Calculating the Cross-sectional Area:
The given dimensions of the square cross section are 40 mm × 40 mm. To calculate the cross-sectional area, we use the formula:
Area = Length × Width
Area = 40 mm × 40 mm = 1600 mm²
Converting Cross-sectional Area to Square Meters:
Since the load is given in Newtons and the length is given in meters, it is necessary to convert the cross-sectional area from square millimeters (mm²) to square meters (m²). There are 1,000,000 mm² in 1 m².
Area = 1600 mm² ÷ 1,000,000 = 0.0016 m²
Calculating the Stress:
The stress in the bar can be calculated using the formula:
Stress = Load ÷ Area
Stress = 200 N ÷ 0.0016 m² = 125,000 N/m²
Converting Stress to Pascals:
Since the modulus of elasticity (C) is given in giga Pascal (GPa), the stress needs to be converted from Newton per square meter (N/m²) to Pascal (Pa). There are 1,000,000,000 Pa in 1 GPa.
Stress = 125,000 N/m² ÷ 1,000,000,000 = 0.000125 GPa
Calculating the Contraction:
The contraction or strain in the bar can be determined using Hooke's Law. Hooke's Law states that strain is directly proportional to stress.
Strain = Stress ÷ Modulus of Elasticity
Strain = 0.000125 GPa ÷ 200 GPa = 0.000000625
The contraction of the bar can be calculated using the formula:
Contraction = Strain × Original Length
Contraction = 0.000000625 × 2 m = 0.00000125 m
Therefore, the contraction of the steel bar will be 0.00000125 meters.
- Cross-sectional area of the steel bar: 40 mm × 40 mm
- Axial compressive load: 200 Newton
- Length of the bar: 2 meters
- C (modulus of elasticity) = 200 GPa (giga Pascal)
Calculating the Cross-sectional Area:
The given dimensions of the square cross section are 40 mm × 40 mm. To calculate the cross-sectional area, we use the formula:
Area = Length × Width
Area = 40 mm × 40 mm = 1600 mm²
Converting Cross-sectional Area to Square Meters:
Since the load is given in Newtons and the length is given in meters, it is necessary to convert the cross-sectional area from square millimeters (mm²) to square meters (m²). There are 1,000,000 mm² in 1 m².
Area = 1600 mm² ÷ 1,000,000 = 0.0016 m²
Calculating the Stress:
The stress in the bar can be calculated using the formula:
Stress = Load ÷ Area
Stress = 200 N ÷ 0.0016 m² = 125,000 N/m²
Converting Stress to Pascals:
Since the modulus of elasticity (C) is given in giga Pascal (GPa), the stress needs to be converted from Newton per square meter (N/m²) to Pascal (Pa). There are 1,000,000,000 Pa in 1 GPa.
Stress = 125,000 N/m² ÷ 1,000,000,000 = 0.000125 GPa
Calculating the Contraction:
The contraction or strain in the bar can be determined using Hooke's Law. Hooke's Law states that strain is directly proportional to stress.
Strain = Stress ÷ Modulus of Elasticity
Strain = 0.000125 GPa ÷ 200 GPa = 0.000000625
The contraction of the bar can be calculated using the formula:
Contraction = Strain × Original Length
Contraction = 0.000000625 × 2 m = 0.00000125 m
Therefore, the contraction of the steel bar will be 0.00000125 meters.
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Steel bar of 40 mm × 40 mm square cross section is subjected to an axial compressive load of 200 Newton if the length of the bar is 2 metre and C is equal to 200 Gamma Pascal solve from the the contraction of the bar will be?
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Steel bar of 40 mm × 40 mm square cross section is subjected to an axial compressive load of 200 Newton if the length of the bar is 2 metre and C is equal to 200 Gamma Pascal solve from the the contraction of the bar will be? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Steel bar of 40 mm × 40 mm square cross section is subjected to an axial compressive load of 200 Newton if the length of the bar is 2 metre and C is equal to 200 Gamma Pascal solve from the the contraction of the bar will be? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Steel bar of 40 mm × 40 mm square cross section is subjected to an axial compressive load of 200 Newton if the length of the bar is 2 metre and C is equal to 200 Gamma Pascal solve from the the contraction of the bar will be?.
Steel bar of 40 mm × 40 mm square cross section is subjected to an axial compressive load of 200 Newton if the length of the bar is 2 metre and C is equal to 200 Gamma Pascal solve from the the contraction of the bar will be? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Steel bar of 40 mm × 40 mm square cross section is subjected to an axial compressive load of 200 Newton if the length of the bar is 2 metre and C is equal to 200 Gamma Pascal solve from the the contraction of the bar will be? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Steel bar of 40 mm × 40 mm square cross section is subjected to an axial compressive load of 200 Newton if the length of the bar is 2 metre and C is equal to 200 Gamma Pascal solve from the the contraction of the bar will be?.
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