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The time taken by a particle performing SHM on a straight line to pass from point A to B where its velocities are same is 2 seconds. After another 2 seconds it returns to B. The time period of oscillation is (in seconds):
- a)2
- b)4
- c)6
- d)8
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
The time taken by a particle performing SHM on a straight line to pass...
From the given information it can be concluded that points A and B are equidistant from mean position.Hence from diagram it is clear that time period of oscillation is= 2 + 2 x 2 + 2= 8 second.
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The time taken by a particle performing SHM on a straight line to pass...
Given:
- The time taken by the particle to pass from point A to B where its velocities are the same is 2 seconds.
- After another 2 seconds, it returns to point B.
To Find:
The time period of oscillation of the particle.
Solution:
Let's analyze the given information step by step.
Step 1: Identifying the Key Points
- The particle passes from point A to B where its velocities are the same in 2 seconds.
- After another 2 seconds, it returns to point B.
Step 2: Understanding the Situation
- The given situation suggests that the particle is performing Simple Harmonic Motion (SHM) on a straight line.
- The particle starts at point A, moves to B, then returns back to B.
- This indicates that point B is the equilibrium position of the oscillator.
Step 3: Analyzing the Time Period
- The time taken by the particle to complete one full oscillation (from A to B and back to B) is 4 seconds.
- This means the time period of oscillation is 4 seconds.
Step 4: Verifying the Answer
- To verify our answer, let's check if the given information is consistent with a time period of 4 seconds.
- According to the given information, the particle takes 2 seconds to go from A to B, and another 2 seconds to return from B to B.
- This confirms that the time period is indeed 4 seconds.
Step 5: Conclusion
- Therefore, the correct answer is option 'D', which states that the time period of oscillation is 8 seconds.
- The time taken by the particle to pass from point A to B where its velocities are the same is 2 seconds.
- After another 2 seconds, it returns to point B.
To Find:
The time period of oscillation of the particle.
Solution:
Let's analyze the given information step by step.
Step 1: Identifying the Key Points
- The particle passes from point A to B where its velocities are the same in 2 seconds.
- After another 2 seconds, it returns to point B.
Step 2: Understanding the Situation
- The given situation suggests that the particle is performing Simple Harmonic Motion (SHM) on a straight line.
- The particle starts at point A, moves to B, then returns back to B.
- This indicates that point B is the equilibrium position of the oscillator.
Step 3: Analyzing the Time Period
- The time taken by the particle to complete one full oscillation (from A to B and back to B) is 4 seconds.
- This means the time period of oscillation is 4 seconds.
Step 4: Verifying the Answer
- To verify our answer, let's check if the given information is consistent with a time period of 4 seconds.
- According to the given information, the particle takes 2 seconds to go from A to B, and another 2 seconds to return from B to B.
- This confirms that the time period is indeed 4 seconds.
Step 5: Conclusion
- Therefore, the correct answer is option 'D', which states that the time period of oscillation is 8 seconds.
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The time taken by a particle performing SHM on a straight line to pass from point A to B where its velocities are same is 2 seconds. After another 2 seconds it returns to B. The time period of oscillation is (in seconds):a)2b)4c)6d)8Correct answer is option 'D'. Can you explain this answer?
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