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The position of a body from a mixed reference point is given by root x is equals to 2 t - 3 where X is metre and t in is second this shows that the body (A) is at rest at t=3/2 (B) is accelerated (C) is decelerated (D) is in uniform motion?
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The position of a body from a mixed reference point is given by root x...
√x =2t-3 x=(2t-3) velocity v=dx/dt = 2(2t-3) × 2 = 4 (2t-3) if V= 0 , t = 3/2 Acceleration, a=dv/dt =4×2=8 So, correct answer is (A) and ( B) .
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The position of a body from a mixed reference point is given by root x is equals to 2 t - 3 where X is metre and t in is second this shows that the body (A) is at rest at t=3/2 (B) is accelerated (C) is decelerated (D) is in uniform motion?
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The position of a body from a mixed reference point is given by root x is equals to 2 t - 3 where X is metre and t in is second this shows that the body (A) is at rest at t=3/2 (B) is accelerated (C) is decelerated (D) is in uniform motion? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about The position of a body from a mixed reference point is given by root x is equals to 2 t - 3 where X is metre and t in is second this shows that the body (A) is at rest at t=3/2 (B) is accelerated (C) is decelerated (D) is in uniform motion? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The position of a body from a mixed reference point is given by root x is equals to 2 t - 3 where X is metre and t in is second this shows that the body (A) is at rest at t=3/2 (B) is accelerated (C) is decelerated (D) is in uniform motion?.
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