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The standard oxidation potentials for oxidation of NADH and H2O are + 0.315 V and 0.815 V, respectively. The standard free energy for oxidation of 1 mole of NADH by oxygen under standard conditions (correct to 1 decimal place) is _______ kJ. [Faraday Constant is 96500 C mole1]Correct answer is between '-219.0,-217.0'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared
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The standard oxidation potentials for oxidation of NADH and H2O are + 0.315 V and 0.815 V, respectively. The standard free energy for oxidation of 1 mole of NADH by oxygen under standard conditions (correct to 1 decimal place) is _______ kJ. [Faraday Constant is 96500 C mole1]Correct answer is between '-219.0,-217.0'. Can you explain this answer?, a detailed solution for The standard oxidation potentials for oxidation of NADH and H2O are + 0.315 V and 0.815 V, respectively. The standard free energy for oxidation of 1 mole of NADH by oxygen under standard conditions (correct to 1 decimal place) is _______ kJ. [Faraday Constant is 96500 C mole1]Correct answer is between '-219.0,-217.0'. Can you explain this answer? has been provided alongside types of The standard oxidation potentials for oxidation of NADH and H2O are + 0.315 V and 0.815 V, respectively. The standard free energy for oxidation of 1 mole of NADH by oxygen under standard conditions (correct to 1 decimal place) is _______ kJ. [Faraday Constant is 96500 C mole1]Correct answer is between '-219.0,-217.0'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice The standard oxidation potentials for oxidation of NADH and H2O are + 0.315 V and 0.815 V, respectively. The standard free energy for oxidation of 1 mole of NADH by oxygen under standard conditions (correct to 1 decimal place) is _______ kJ. [Faraday Constant is 96500 C mole1]Correct answer is between '-219.0,-217.0'. Can you explain this answer? tests, examples and also practice IIT JAM tests.