Mass = 2000
v. =. 36km/h
work done = ?
now ,
work done = kinetic energy
work done = 1/2 mv2
work done= 1/2 *2000*(36)'2
work done = 1/2*2000* 1296
work done = 1/2 *2592000
work done= 2592000/2
work done= 1296000 joule

Mass of the bus: 2000 kg
Velocity of the bus: 36 km/h

To calculate the work required to stop the bus, we need to first convert the velocity from km/h to m/s.

Converting velocity from km/h to m/s:
1 km/h = 1000 m/3600 s
36 km/h = (36 x 1000) / 3600 m/s
36 km/h = 10 m/s

Now that we have the velocity in m/s, we can use the formula for work:

Work (W) = Force (F) x Distance (d)

In this case, the force required to stop the bus is the force of friction opposing its motion, which can be calculated using Newton's second law of motion:

Force (F) = Mass (m) x Acceleration (a)

Since we want to stop the bus, the acceleration (a) will be negative, indicating deceleration.

Calculating the force required:
Mass (m) = 2000 kg
Acceleration (a) = -10 m/s^2 (negative because the bus is decelerating)

Force (F) = 2000 kg x (-10 m/s^2)
Force (F) = -20,000 N

Now we can calculate the work required using the given velocity and the force:

Calculating the work:
Work (W) = Force (F) x Distance (d)

The distance (d) required to stop the bus is not given in the question, so we cannot calculate the exact work. However, we can provide the formula for work:

Work (W) = 1/2 x Mass (m) x Velocity^2 (v^2)

Using this formula, we can calculate the work required to stop the bus:

Work (W) = 1/2 x 2000 kg x (10 m/s)^2
Work (W) = 1/2 x 2000 kg x 100 m^2/s^2
Work (W) = 100,000 J

Therefore, the work required to stop the bus is 100,000 Joules.