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In the final semester, an engineering college offers three elective courses and one mandatory course. A student has to register for exactly three courses: two electives and the mandatory course. The registration in three of the four courses is: 45, 55 and 70. What will be the number of students in the elective with the lowest registration?
  • a)
    35
  • b)
    40
  • c)
    42
  • d)
    45
  • e)
    Either B or D
Correct answer is option 'E'. Can you explain this answer?
Verified Answer
In the final semester, an engineering college offers three elective c...
The number of candidates registered for 3 of the 4 courses is 45, 55, and 70.
There are 2 cases.
70 can be the total number of students registered in an elective or the mandatory course.
Case (i):
70 students have registered in an elective.
Each student will choose 2 elective.
=> Total number of electives chosen = 2* total number of students.
45+55+70 = 2*number of students.
Number of students = 170/2 = 85.
In this case, at least 45 students would have selected an elective.
Case (ii):
70 students have registered in the mandatory class.
=> 45+55+x = 2*70
=> x =40.
As we can see, the number of students registered in an elective can be 40 or 45. Therefore, option E is the right answer.
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Most Upvoted Answer
In the final semester, an engineering college offers three elective c...
To find the number of students in the elective with the lowest registration, we need to understand the given information.

Given:
- There are three elective courses and one mandatory course.
- A student has to register for exactly three courses: two electives and the mandatory course.
- The registration in three of the four courses is: 45, 55, and 70.

Let's analyze the given information step by step.

Step 1: Identify the mandatory course registration
- The mandatory course registration is not given explicitly.
- However, since a student has to register for exactly three courses, we can assume that the remaining course (not mentioned in the given registrations) is the mandatory course.
- Therefore, the registration for the mandatory course can be assumed to be the remaining value after deducting the sum of the three given registrations from the total number of students in the college.

Step 2: Calculate the total number of students in the college
- The total number of students in the college can be calculated by summing up the registrations of the three given courses.
- Total = 45 + 55 + 70 = 170

Step 3: Calculate the registration for the mandatory course
- The registration for the mandatory course can be calculated by subtracting the sum of the three given registrations from the total number of students in the college.
- Mandatory Course Registration = Total - (Registration1 + Registration2 + Registration3)
- Mandatory Course Registration = 170 - (45 + 55 + 70) = 170 - 170 = 0

Step 4: Calculate the number of students in the elective with the lowest registration
- Since the registration for the mandatory course is 0, we can determine the number of students in the elective with the lowest registration by finding the minimum among the three given registrations.
- The minimum registration among 45, 55, and 70 is 45.
- Therefore, the number of students in the elective with the lowest registration is 45.

Hence, the correct answer is option 'E', i.e., Either B or D.
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In the final semester, an engineering college offers three elective courses and one mandatory course. A student has to register for exactly three courses: two electives and the mandatory course. The registration in three of the four courses is: 45, 55 and 70. What will be the number of students in the elective with the lowest registration?a)35b)40c)42d)45e)Either B or DCorrect answer is option 'E'. Can you explain this answer?
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