Explanation of the problem:

The problem requires us to determine the acceleration of a car that starts from rest and acquires a velocity of 54 km/h in 2 seconds. The acceleration is a measure of how fast the velocity of an object changes with time. It is given by the formula:

Acceleration (a) = Change in velocity (v) / Time taken (t)

Calculation:

Given, initial velocity (u) = 0 km/h
Final velocity (v) = 54 km/h
Time taken (t) = 2 s

We need to convert the final velocity from km/h to m/s since the SI unit of acceleration is meters per second squared (m/s^2).

1 km/h = 0.2778 m/s
Therefore, final velocity (v) = (54 × 0.2778) m/s = 15 m/s

Now, we can substitute the values in the formula for acceleration:

Acceleration (a) = (15 - 0) m/s / 2 s = 7.5 m/s^2

Therefore, the acceleration of the car is 7.5 m/s^2.

Conclusion:

The car has an acceleration of 7.5 m/s^2. This means that every second, the car's velocity increases by 7.5 m/s. The problem highlights the importance of the concept of acceleration in determining the motion of an object.

As the car is starting from rest ,
Initial velocity = u = 0 m/s
Final velocity = v = 54 km/hr 
To convert km/hr to m/s , we multiply it by 5/18
Final velocity = v = 54 km/hr = 54 x 5/18
= 15 m/s
Time = t = 2 sec
a = acceleration
Equation of motion :v = u + at
15 = 0 + 2a
a = 15/2 = 7.5 m/s²

s = distance traveled
Equation of motion :s = ut + 1/2 at²
= 0 + 1/2 × 7.5 × 2² = 15 metres