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A circular ring of diameter 40cm and mass 1kg is rotating about an axis normal to its plane and passing through the centre with a frequency of 10 rotations per second. Calculate the angular momentum about its axis of rotation?
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A circular ring of diameter 40cm and mass 1kg is rotating about an axi...
Given:
Diameter of the circular ring (d) = 40 cm
Radius of the circular ring (r) = d/2 = 20 cm = 0.2 m
Mass of the circular ring (m) = 1 kg
Frequency of rotation (f) = 10 rotations per second

Formula:
The formula to calculate angular momentum (L) is given by:
L = Iω
where,
I = Moment of inertia
ω = Angular velocity

Calculation:
Step 1: Convert the diameter of the circular ring from cm to m
Diameter (d) = 40 cm = 0.4 m

Step 2: Calculate the moment of inertia (I) of the circular ring
The moment of inertia of a circular ring rotating about an axis passing through its center and perpendicular to its plane is given by the formula:
I = 0.5 * m * r^2
where,
m = mass of the circular ring
r = radius of the circular ring

Substituting the values, we get:
I = 0.5 * 1 kg * (0.2 m)^2
I = 0.02 kg.m^2

Step 3: Calculate the angular velocity (ω) of the circular ring
Angular velocity (ω) is given by the formula:
ω = 2πf
where,
f = frequency of rotation

Substituting the values, we get:
ω = 2 * 3.14 * 10 rad/s
ω = 62.8 rad/s

Step 4: Calculate the angular momentum (L) of the circular ring
Using the formula L = Iω, we can calculate the angular momentum:
L = 0.02 kg.m^2 * 62.8 rad/s
L = 1.256 kg.m^2/s

Answer:
The angular momentum of the circular ring about its axis of rotation is 1.256 kg.m^2/s.
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A circular ring of diameter 40cm and mass 1kg is rotating about an axis normal to its plane and passing through the centre with a frequency of 10 rotations per second. Calculate the angular momentum about its axis of rotation?
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