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A body of mass 1kg is placed at a distance of 2m from another body of mass 10 kg. At what distance from the body of 1 kg , another body of mass 5 kg be placed so that the net force of gravitation acting on the body of mass 1 kg is Zero. [1] √3 m [2] √2m [3] √5m [4] √6m
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A body of mass 1kg is placed at a distance of 2m from another body of ...
Dekho net gravitational force on the body of mass 1 kg is zero Is ka mtlb 5 kg, 1 kg and 1 kg, 10 kg ke beech mai jo force hai woh equal and opposite in direction hoga Toh dono forces ko equate kr do ans mil jaye ga
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A body of mass 1kg is placed at a distance of 2m from another body of ...
The gravitational force between two objects is given by the equation F = G * (m1 * m2) / r^2, where F is the gravitational force, G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between the centers of the two objects.
In this problem, we have a body of mass 1 kg and a body of mass 10 kg placed at a distance of 2 m. We need to find the distance from the body of 1 kg where another body of mass 5 kg should be placed so that the net force of gravitation acting on the body of 1 kg is zero.
Let's assume that the distance from the body of 1 kg to the new body of mass 5 kg is x.
To find the distance x, we need to equate the gravitational forces between the body of 1 kg and the body of 10 kg, and the body of 1 kg and the body of 5 kg, so that the net force is zero.
1. Gravitational force between the body of 1 kg and the body of 10 kg:
F1 = G * (m1 * m2) / r^2
= G * (1 kg * 10 kg) / (2 m)^2
= G * (10 kg) / 4
2. Gravitational force between the body of 1 kg and the body of 5 kg:
F2 = G * (m1 * m2) / r^2
= G * (1 kg * 5 kg) / (x)^2
= G * (5 kg) / (x^2)
Since the net force is zero, F1 - F2 = 0.
G * (10 kg) / 4 - G * (5 kg) / (x^2) = 0
Simplifying the equation:
10 / 4 - 5 / (x^2) = 0
10 / 4 = 5 / (x^2)
2.5 = 5 / (x^2)
x^2 = 5 / 2.5
x^2 = 2
x = √2
Therefore, the distance from the body of 1 kg where another body of mass 5 kg should be placed so that the net force of gravitation acting on the body of 1 kg is zero is √2 m.
So, the correct answer is option [2] √2m.
In this problem, we have a body of mass 1 kg and a body of mass 10 kg placed at a distance of 2 m. We need to find the distance from the body of 1 kg where another body of mass 5 kg should be placed so that the net force of gravitation acting on the body of 1 kg is zero.
Let's assume that the distance from the body of 1 kg to the new body of mass 5 kg is x.
To find the distance x, we need to equate the gravitational forces between the body of 1 kg and the body of 10 kg, and the body of 1 kg and the body of 5 kg, so that the net force is zero.
1. Gravitational force between the body of 1 kg and the body of 10 kg:
F1 = G * (m1 * m2) / r^2
= G * (1 kg * 10 kg) / (2 m)^2
= G * (10 kg) / 4
2. Gravitational force between the body of 1 kg and the body of 5 kg:
F2 = G * (m1 * m2) / r^2
= G * (1 kg * 5 kg) / (x)^2
= G * (5 kg) / (x^2)
Since the net force is zero, F1 - F2 = 0.
G * (10 kg) / 4 - G * (5 kg) / (x^2) = 0
Simplifying the equation:
10 / 4 - 5 / (x^2) = 0
10 / 4 = 5 / (x^2)
2.5 = 5 / (x^2)
x^2 = 5 / 2.5
x^2 = 2
x = √2
Therefore, the distance from the body of 1 kg where another body of mass 5 kg should be placed so that the net force of gravitation acting on the body of 1 kg is zero is √2 m.
So, the correct answer is option [2] √2m.
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A body of mass 1kg is placed at a distance of 2m from another body of mass 10 kg. At what distance from the body of 1 kg , another body of mass 5 kg be placed so that the net force of gravitation acting on the body of mass 1 kg is Zero. [1] √3 m [2] √2m [3] √5m [4] √6m
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A body of mass 1kg is placed at a distance of 2m from another body of mass 10 kg. At what distance from the body of 1 kg , another body of mass 5 kg be placed so that the net force of gravitation acting on the body of mass 1 kg is Zero. [1] √3 m [2] √2m [3] √5m [4] √6m for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A body of mass 1kg is placed at a distance of 2m from another body of mass 10 kg. At what distance from the body of 1 kg , another body of mass 5 kg be placed so that the net force of gravitation acting on the body of mass 1 kg is Zero. [1] √3 m [2] √2m [3] √5m [4] √6m covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body of mass 1kg is placed at a distance of 2m from another body of mass 10 kg. At what distance from the body of 1 kg , another body of mass 5 kg be placed so that the net force of gravitation acting on the body of mass 1 kg is Zero. [1] √3 m [2] √2m [3] √5m [4] √6m.
A body of mass 1kg is placed at a distance of 2m from another body of mass 10 kg. At what distance from the body of 1 kg , another body of mass 5 kg be placed so that the net force of gravitation acting on the body of mass 1 kg is Zero. [1] √3 m [2] √2m [3] √5m [4] √6m for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A body of mass 1kg is placed at a distance of 2m from another body of mass 10 kg. At what distance from the body of 1 kg , another body of mass 5 kg be placed so that the net force of gravitation acting on the body of mass 1 kg is Zero. [1] √3 m [2] √2m [3] √5m [4] √6m covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body of mass 1kg is placed at a distance of 2m from another body of mass 10 kg. At what distance from the body of 1 kg , another body of mass 5 kg be placed so that the net force of gravitation acting on the body of mass 1 kg is Zero. [1] √3 m [2] √2m [3] √5m [4] √6m.
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