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If ω is a cube root of unity then the value of (1−ω8)(1−ω4)(1−ω2)(1−ω) is ___
  • a)
    1
  • b)
    9
  • c)
    0
  • d)
    6
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
If ω is a cube root of unity then the value of(1−ω8)...
We know that 1+ω+ω2=0 and ω3 =1 then
(1−ω8)(1−ω4)(1−ω2)(1−ω) = (1−ω2)(1−ω)(1−ω2)(1−ω)
= (1−ω2−ω+ω3)(1−ω2−ω+ω3)
= (2−(ω+ω2))(2−(ω+ω2))
= (2−(−1))(2−(−1)) = 9
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If ω is a cube root of unity then the value of(1−ω8)(1−ω4)(1−ω2)(1−ω) is ___a)1b)9c)0d)6Correct answer is option 'B'. Can you explain this answer?
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