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A C5H13N compound gives a base soluble derivative in the Hinsberg’s test. Which of the following best satisfy this condition?
  • a)
    N, N-diethyl propyl amine
  • b)
    Isopropyl dimethyl amine
  • c)
    2, 2-dimethyl propyl amine
  • d)
    N-methyl-2-methyl propyl amine
Correct answer is option 'C'. Can you explain this answer?
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A C5H13N compound gives a base soluble derivative in the Hinsbergs tes...
Answer:

The Hinsberg test is used to differentiate between primary, secondary, and tertiary amines based on their solubility in a specific reagent. In this test, the amine is reacted with benzene sulfonyl chloride (C6H5SO2Cl) in the presence of an alkali (NaOH) to form a sulfonamide derivative. The solubility of this sulfonamide derivative in a strong alkali solution is then tested.

In order for a compound to give a base soluble derivative in the Hinsberg test, it must have a substituent group that allows the formation of a stable sulfonamide derivative. Let's analyze each option to determine which one satisfies this condition:

a) N, N-diethyl propyl amine: This compound has two ethyl groups attached to the nitrogen atom. When reacted with benzene sulfonyl chloride, it will form a sulfonamide with two ethyl groups. However, this sulfonamide is not stable and will not be soluble in a strong alkali solution.

b) Isopropyl dimethyl amine: This compound has two methyl groups and one isopropyl group attached to the nitrogen atom. When reacted with benzene sulfonyl chloride, it will form a sulfonamide with two methyl groups and one isopropyl group. However, this sulfonamide is not stable and will not be soluble in a strong alkali solution.

c) 2, 2-dimethyl propyl amine: This compound has one methyl group and one 2,2-dimethylpropyl group attached to the nitrogen atom. When reacted with benzene sulfonyl chloride, it will form a sulfonamide with one methyl group and one 2,2-dimethylpropyl group. This sulfonamide is stable and will be soluble in a strong alkali solution.

d) N-methyl-2-methyl propyl amine: This compound has one methyl group and one 2-methylpropyl group attached to the nitrogen atom. When reacted with benzene sulfonyl chloride, it will form a sulfonamide with one methyl group and one 2-methylpropyl group. However, this sulfonamide is not stable and will not be soluble in a strong alkali solution.

Therefore, the only compound that satisfies the condition of giving a base soluble derivative in the Hinsberg test is option 'C', 2,2-dimethyl propyl amine.
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A C5H13N compound gives a base soluble derivative in the Hinsbergs tes...
Primary amine reacts with tosyl chloride to give sulphonamide which dissolve in KOH
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A C5H13N compound gives a base soluble derivative in the Hinsbergs test. Which of the following best satisfy this condition?a)N, N-diethyl propyl amineb)Isopropyl dimethyl aminec)2, 2-dimethyl propyl amined)N-methyl-2-methyl propyl amineCorrect answer is option 'C'. Can you explain this answer?
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A C5H13N compound gives a base soluble derivative in the Hinsbergs test. Which of the following best satisfy this condition?a)N, N-diethyl propyl amineb)Isopropyl dimethyl aminec)2, 2-dimethyl propyl amined)N-methyl-2-methyl propyl amineCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A C5H13N compound gives a base soluble derivative in the Hinsbergs test. Which of the following best satisfy this condition?a)N, N-diethyl propyl amineb)Isopropyl dimethyl aminec)2, 2-dimethyl propyl amined)N-methyl-2-methyl propyl amineCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A C5H13N compound gives a base soluble derivative in the Hinsbergs test. Which of the following best satisfy this condition?a)N, N-diethyl propyl amineb)Isopropyl dimethyl aminec)2, 2-dimethyl propyl amined)N-methyl-2-methyl propyl amineCorrect answer is option 'C'. Can you explain this answer?.
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