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When sulphuric acid reacts with PCI5, sulphuryl chloride is formed as the final product. This shows that sulphuric acid is
  • a)
    a dibasic acid
  • b)
    has great affinity for water
  • c)
    has two hydroxyl groups in its structure
  • d)
    is a derivative of sulphur dioxide
Correct answer is option 'C'. Can you explain this answer?
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When sulphuric acid reacts with PCI5, sulphuryl chloride is formed as the final product. This shows that sulphuric acid isa)a dibasic acidb)has great affinity for waterc)has two hydroxyl groups in its structured)is a derivative of sulphur dioxideCorrect answer is option 'C'. Can you explain this answer?
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When sulphuric acid reacts with PCI5, sulphuryl chloride is formed as the final product. This shows that sulphuric acid isa)a dibasic acidb)has great affinity for waterc)has two hydroxyl groups in its structured)is a derivative of sulphur dioxideCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about When sulphuric acid reacts with PCI5, sulphuryl chloride is formed as the final product. This shows that sulphuric acid isa)a dibasic acidb)has great affinity for waterc)has two hydroxyl groups in its structured)is a derivative of sulphur dioxideCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When sulphuric acid reacts with PCI5, sulphuryl chloride is formed as the final product. This shows that sulphuric acid isa)a dibasic acidb)has great affinity for waterc)has two hydroxyl groups in its structured)is a derivative of sulphur dioxideCorrect answer is option 'C'. Can you explain this answer?.
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