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If x=cosθ+jsinθ the value of  is
  • a)
    2 cos nθ 
  • b)
    2j sin nθ
  • c)
    2 sin nθ
  • d)
    2j cos nθ
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
If x=cosθ+jsinθ the value ofisa)2 cos nθb)2j sin n&t...
We can write xn=cosnθ+jsinnθ
The given equation can be written as 
=cosnθ+jsinnθ+cosnθ−jsinnθ
=2cosnθ
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If x=cosθ+jsinθ the value ofisa)2 cos nθb)2j sin nθc)2 sin nθd)2j cos nθCorrect answer is option 'A'. Can you explain this answer?
Question Description
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