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If (2n + 1) + (2n + 3) + (2n + 5) + ... + (2n + 47) = 5280, then what is the value of 1 + 2 + 3 +... + n?
Correct answer is '4851'. Can you explain this answer?
Verified Answer
If (2n + 1) + (2n + 3) + (2n + 5) + ... + (2n + 47) = 5280, then what...
Let us first find the number of terms
47=1+ (n-1)2
n=24
24*2n+1+3+5+....47=5280
48n+576=5280
48n=4704
n=98
Sum of first 98 terms = 98*99/2
=4851
Positive Mark: 3
Negative Mark: 0
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If (2n + 1) + (2n + 3) + (2n + 5) + ... + (2n + 47) = 5280, then what is the value of 1 + 2 + 3 +... + n?Correct answer is '4851'. Can you explain this answer?
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