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An electron and a proton starting from rest get accelerated through potential difference of 100kV. The final speeds of the electron and the proton are Ve and Vp respectively. Which of the following relations is correct?
  • a)
    Ve > Vp
  • b)
    Ve < Vp
  • c)
    Ve = Vp
  • d)
    Cannot be determined
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
An electron and a proton starting from rest get accelerated through po...
Both when accelerated through a potential difference of 100KV, they will have the same energy. The mass of the electron is less than the mass of a proton, hence it will move faster (momentum).
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Most Upvoted Answer
An electron and a proton starting from rest get accelerated through po...

Explanation:

Given:
- Potential difference = 100 kV
- Electron and proton are accelerated through the potential difference
- Final speeds of electron and proton are Ve and Vp respectively

Analysis:
- The speed of a charged particle after being accelerated through a potential difference can be calculated using the formula: \( v = \sqrt{\frac{2qV}{m}} \)
- Where v is the speed of the particle, q is the charge of the particle, V is the potential difference, and m is the mass of the particle.

Comparison:
- For an electron (negatively charged particle), q is negative and m is small compared to a proton.
- For a proton (positively charged particle), q is positive and m is larger compared to an electron.
- Since the mass of the proton is larger than the mass of the electron, the speed of the electron (Ve) will be greater than the speed of the proton (Vp) when accelerated through the same potential difference.

Conclusion:
- Therefore, the correct relation is Ve > Vp.
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An electron and a proton starting from rest get accelerated through potential difference of 100kV. The final speeds of the electron and the proton are Ve and Vp respectively. Which of the following relations is correct?a)Ve > Vpb)Ve < Vpc)Ve = Vpd)Cannot be determinedCorrect answer is option 'A'. Can you explain this answer?
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