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Statement I : 2 g of benzoic acid (C6H5COOH) in 25.0 g of benzene lowered the freezing point of benzene by 1.62 K. Kf (benzene) = 4.86 K kg mol-1.Statement II : Depression in freezing point is a colligative property.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is correct but Statement I is incorrectCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Statement I : 2 g of benzoic acid (C6H5COOH) in 25.0 g of benzene lowered the freezing point of benzene by 1.62 K. Kf (benzene) = 4.86 K kg mol-1.Statement II : Depression in freezing point is a colligative property.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is correct but Statement I is incorrectCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Statement I : 2 g of benzoic acid (C6H5COOH) in 25.0 g of benzene lowered the freezing point of benzene by 1.62 K. Kf (benzene) = 4.86 K kg mol-1.Statement II : Depression in freezing point is a colligative property.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is correct but Statement I is incorrectCorrect answer is option 'B'. Can you explain this answer?.

Solutions for Statement I : 2 g of benzoic acid (C6H5COOH) in 25.0 g of benzene lowered the freezing point of benzene by 1.62 K. Kf (benzene) = 4.86 K kg mol-1.Statement II : Depression in freezing point is a colligative property.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is correct but Statement I is incorrectCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of Statement I : 2 g of benzoic acid (C6H5COOH) in 25.0 g of benzene lowered the freezing point of benzene by 1.62 K. Kf (benzene) = 4.86 K kg mol-1.Statement II : Depression in freezing point is a colligative property.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is correct but Statement I is incorrectCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Statement I : 2 g of benzoic acid (C6H5COOH) in 25.0 g of benzene lowered the freezing point of benzene by 1.62 K. Kf (benzene) = 4.86 K kg mol-1.Statement II : Depression in freezing point is a colligative property.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is correct but Statement I is incorrectCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for Statement I : 2 g of benzoic acid (C6H5COOH) in 25.0 g of benzene lowered the freezing point of benzene by 1.62 K. Kf (benzene) = 4.86 K kg mol-1.Statement II : Depression in freezing point is a colligative property.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is correct but Statement I is incorrectCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of Statement I : 2 g of benzoic acid (C6H5COOH) in 25.0 g of benzene lowered the freezing point of benzene by 1.62 K. Kf (benzene) = 4.86 K kg mol-1.Statement II : Depression in freezing point is a colligative property.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is correct but Statement I is incorrectCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Statement I : 2 g of benzoic acid (C6H5COOH) in 25.0 g of benzene lowered the freezing point of benzene by 1.62 K. Kf (benzene) = 4.86 K kg mol-1.Statement II : Depression in freezing point is a colligative property.a)Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement Ib)Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is correct but Statement I is incorrectCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice JEE tests.