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Considering two opposite vertices of a square of side ‘a’ as centres, two circular arcs are drawn within the square joining the other two vertices, thus forming two sectors. What is the common area in these two sectors?
  • a)
  • b)
  • c)
  • d)
Correct answer is option 'C'. Can you explain this answer?
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Considering two opposite vertices of a square of side ‘a’ ...

Area of leaf BEDFB = Area of two quarter circle – area of square
= 2πr2/4 – a2
= πa2/2 – a2 = a2(π/2 - 1)
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Considering two opposite vertices of a square of side ‘a’ ...
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Considering two opposite vertices of a square of side ‘a’ ...

Area of leaf BEDFB = Area of two quarter circle – area of square
= 2πr2/4 – a2
= πa2/2 – a2 = a2(π/2 - 1)
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