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The angles of a triangle are in the ratio 1 : 1 : 4. If the perimeter of the triangle is k times its largest side, then what is the value of k?
  • a)
  • b)
  • c)
  • d)
    2
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
The angles of a triangle are in the ratio 1 : 1 : 4. If the perimeter ...
4k + k + k = 6x =180 degrees
k= 30 degrees
So triangle is 30,30 and 120 degrees
Let sides of triangle be x,x and y units with y being the largest side opposite to 120 degree angle
Using cosine law
Cos 120 = - sin 30 = -1/2 = (2x2 – y2)/2x2
So 3x2 = y2 …. (i)
Given Perimeter = k (Largest side)
Or 2x+y = ky
Putting value of x from eq (i)
2y/√3 + y = ky
K = 2/√3 + 1
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Most Upvoted Answer
The angles of a triangle are in the ratio 1 : 1 : 4. If the perimeter ...
4k + k + k = 6x =180 degrees
k= 30 degrees
So triangle is 30,30 and 120 degrees
Let sides of triangle be x,x and y units with y being the largest side opposite to 120 degree angle
Using cosine law
Cos 120 = - sin 30 = -1/2 = (2x2 – y2)/2x2
So 3x2 = y2 …. (i)
Given Perimeter = k (Largest side)
Or 2x+y = ky
Putting value of x from eq (i)
2y/√3 + y = ky
K = 2/√3 + 1
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The angles of a triangle are in the ratio 1 : 1 : 4. If the perimeter of the triangle is k times its largest side, then what is the value of k?a)b)c)d)2Correct answer is option 'A'. Can you explain this answer?
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