There are two parallel streets each directed north to south. A person ...
Initially the person is travelling from south to north i.e. D to A
He takes 150
o right turn and moves AB distance and then he takes 60
o left turn travels BC
AB = 20km/hr * 15/60 hr = 5km
BC = 30 * 20/60 = 10 km
We know that distance between both the streets is DC = DB + BC
DB = AB cos 60
o = 5. ½ = 2.5 km
So the distance between streets = 12.5 km
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There are two parallel streets each directed north to south. A person ...
Distance between the two streets
Given information:
- Two parallel streets, both directed north to south.
- A person in the first street is traveling from south to north.
- The person wants to take the second street which is on his right side.
- The person makes a 150° turn to the right and travels for 15 minutes at a speed of 20 km/hr.
- Then, the person takes a left turn of 60° and travels for 20 minutes at a speed of 30 km/hr in order to meet the second street.
To find the distance between the two streets, we can break down the person's movements into vectors and use trigonometry to find the distance.
Calculating the first vector:
- The person makes a 150° turn to the right and travels for 15 minutes at a speed of 20 km/hr.
- The distance covered in this vector can be calculated using the formula: distance = speed × time.
- Therefore, the distance covered in this vector is 20 km/hr × (15/60) hr = 5 km.
Calculating the second vector:
- The person takes a left turn of 60° and travels for 20 minutes at a speed of 30 km/hr.
- Again, using the formula distance = speed × time, the distance covered in this vector is 30 km/hr × (20/60) hr = 10 km.
Calculating the resultant vector:
- The resultant vector is the vector formed by adding the two vectors calculated above.
- This can be done using the cosine rule: c² = a² + b² - 2abcos(C), where c is the magnitude of the resultant vector, a and b are the magnitudes of the individual vectors, and C is the angle between them.
- Plugging in the values, we have: c² = 5² + 10² - 2(5)(10)cos(150°).
- Solving this equation gives us: c ≈ 12.5 km.
Therefore, the distance between the two streets is approximately 12.5 km.
Hence, the correct answer is option C.
There are two parallel streets each directed north to south. A person ...
Initially the person is travelling from south to north i.e. D to A
He takes 150
o right turn and moves AB distance and then he takes 60
o left turn travels BC
AB = 20km/hr * 15/60 hr = 5km
BC = 30 * 20/60 = 10 km
We know that distance between both the streets is DC = DB + BC
DB = AB cos 60
o = 5. ½ = 2.5 km
So the distance between streets = 12.5 km