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Reference frame P' moves with respect to another A frame P with a uniform velocity v. Write down the transformations giving x, y, z', t' in terms of x, y, z, t in Lorentz form. (The frames coincide at t = 0).Show that for values of v < c,="" lorentz="" transformation="" reduces="" to="" the="" galilean="" one?="" c,="" lorentz="" transformation="" reduces="" to="" the="" galilean="" />
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Reference frame P' moves with respect to another A frame P with a unif...
Transformation equations in Lorentz form

The transformations between the two reference frames can be described using the Lorentz transformation equations. Let's consider a reference frame P' that moves with a uniform velocity v with respect to another reference frame A frame P. The frames coincide at t = 0.

The Lorentz transformation equations relate the coordinates and time measured in the two frames. In this case, we can write the transformations for x, y, z', and t' in terms of x, y, z, and t as follows:

x' = γ(x - vt)
y' = y
z' = z
t' = γ(t - vx/c^2)

Here, γ is the Lorentz factor given by γ = 1 / √(1 - (v^2/c^2)), where c is the speed of light in vacuum.

Explanation and analysis

The Lorentz transformation equations describe how the coordinates and time measurements in one reference frame relate to those in another reference frame that is moving relative to the first frame. Let's analyze the transformations in more detail:

1. x' = γ(x - vt): This equation represents the transformation of the x-coordinate in the moving frame P' to the x-coordinate in the stationary frame P. It takes into account the contraction of lengths in the direction of motion.

2. y' = y: This equation states that the y-coordinate in the moving frame P' remains the same as the y-coordinate in the stationary frame P. There is no effect on the y-coordinate due to the relative motion between the frames.

3. z' = z: Similarly, the z-coordinate in the moving frame P' remains the same as the z-coordinate in the stationary frame P. There is no effect on the z-coordinate due to the relative motion between the frames.

4. t' = γ(t - vx/c^2): This equation represents the transformation of time between the frames. It takes into account the time dilation effect, where the time measured in the moving frame P' appears to run slower compared to the stationary frame P. The term vx/c^2 accounts for the time delay caused by the motion.

For small values of v (much smaller than the speed of light c), the Lorentz factor γ approaches 1, and the transformations reduce to the classical Galilean transformations. In this case, the length contraction and time dilation effects are negligible.

Overall, the Lorentz transformation equations provide a mathematical framework for understanding how measurements of space and time in one reference frame relate to those in another reference frame that is moving relative to the first frame. These equations are fundamental in the theory of special relativity.
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Reference frame P' moves with respect to another A frame P with a uniform velocity v. Write down the transformations giving x, y, z', t' in terms of x, y, z, t in Lorentz form. (The frames coincide at t = 0).Show that for values of v
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