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Two shafts A and B are of same length and subjected to same torque T. If the diameter of shaft B is twice that of shaft A, the ratio of shear stresses developed in shafts A and B is
  • a)
    8
  • b)
    1/8
  • c)
    1
  • d)
    1/2
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Two shafts A and B are of same length and subjected to same torque T....
Given: We know,
τ =
= 23 = 8
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Most Upvoted Answer
Two shafts A and B are of same length and subjected to same torque T....
Explanation:

To find the ratio of shear stresses developed in shafts A and B, we can use the formula for shear stress:

Shear stress (τ) = Torque (T) / Polar moment of inertia (J)

The polar moment of inertia (J) is given by:

J = π/32 * (d^4 - d_i^4)

Where,
d = diameter of the shaft
d_i = inner diameter of the shaft

Step 1: Finding the polar moment of inertia for shaft A
Let the diameter of shaft A be 'd'. Since the diameter of shaft B is twice that of shaft A, the diameter of shaft B will be '2d'.
The inner diameter of both shafts is not given, so we can assume it to be negligible. Therefore, d_i = 0.

J_A = π/32 * (d^4 - 0^4)
= π/32 * d^4

Step 2: Finding the polar moment of inertia for shaft B
J_B = π/32 * ((2d)^4 - 0^4)
= π/32 * 16d^4
= 4π/32 * d^4
= π/8 * d^4

Step 3: Finding the ratio of shear stresses
The torque applied on both shafts A and B is the same, i.e., T.

So, the ratio of shear stresses developed in shafts A and B is given by:

τ_A / τ_B = T / J_A / (T / J_B)
= J_B / J_A
= (π/8 * d^4) / (π/32 * d^4)
= (1/8)

Therefore, the ratio of shear stresses developed in shafts A and B is 1/8.

Hence, the correct answer is option A.
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Two shafts A and B are of same length and subjected to same torque T. If the diameter of shaft B is twice that of shaft A, the ratio of shear stresses developed in shafts A and B isa) 8b) 1/8c) 1d) 1/2Correct answer is option 'A'. Can you explain this answer?
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