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the vapour pressure of solution having 2.0 g of solute x ( gram atomic mass - 32 g mol-1 ) in 100 g of co2( vapour pressure - 854 torr) is 848.9 torr. The molecular formula of the solute is
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the vapour pressure of solution having 2.0 g of solute x ( gram atomic...
Calculation of Molecular Formula of Solute
- First, calculate the moles of solute X in the solution using the given mass of solute and its molar mass.
- Moles of X = 2.0 g / 32 g mol-1 = 0.0625 mol
- Next, use the given vapor pressure of the solution and the vapor pressure of pure CO2 to calculate the mole fraction of X in the solution.
- Vapor pressure of pure CO2 = 854 torr
- Vapor pressure of solution = 848.9 torr
- Mole fraction of X = (P1 - P2) / P1 = (854 - 848.9) / 854 = 0.0059
- Now, calculate the moles of CO2 in the solution using the mole fraction of X.
- Moles of CO2 = 100 g / 44 g mol-1 = 2.27 mol
- Moles of X = 0.0625 mol
- Moles of CO2 = 2.27 mol - 0.0625 mol = 2.2075 mol
- Finally, determine the molecular formula of solute X using the moles of X and its molar mass.
- Molecular formula = (moles of X) x (gram atomic mass) = 0.0625 x 32 = 2
Therefore, the molecular formula of the solute X is X2.
- First, calculate the moles of solute X in the solution using the given mass of solute and its molar mass.
- Moles of X = 2.0 g / 32 g mol-1 = 0.0625 mol
- Next, use the given vapor pressure of the solution and the vapor pressure of pure CO2 to calculate the mole fraction of X in the solution.
- Vapor pressure of pure CO2 = 854 torr
- Vapor pressure of solution = 848.9 torr
- Mole fraction of X = (P1 - P2) / P1 = (854 - 848.9) / 854 = 0.0059
- Now, calculate the moles of CO2 in the solution using the mole fraction of X.
- Moles of CO2 = 100 g / 44 g mol-1 = 2.27 mol
- Moles of X = 0.0625 mol
- Moles of CO2 = 2.27 mol - 0.0625 mol = 2.2075 mol
- Finally, determine the molecular formula of solute X using the moles of X and its molar mass.
- Molecular formula = (moles of X) x (gram atomic mass) = 0.0625 x 32 = 2
Therefore, the molecular formula of the solute X is X2.
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the vapour pressure of solution having 2.0 g of solute x ( gram atomic mass - 32 g mol-1 ) in 100 g of co2( vapour pressure - 854 torr) is 848.9 torr. The molecular formula of the solute is
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the vapour pressure of solution having 2.0 g of solute x ( gram atomic mass - 32 g mol-1 ) in 100 g of co2( vapour pressure - 854 torr) is 848.9 torr. The molecular formula of the solute is for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about the vapour pressure of solution having 2.0 g of solute x ( gram atomic mass - 32 g mol-1 ) in 100 g of co2( vapour pressure - 854 torr) is 848.9 torr. The molecular formula of the solute is covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for the vapour pressure of solution having 2.0 g of solute x ( gram atomic mass - 32 g mol-1 ) in 100 g of co2( vapour pressure - 854 torr) is 848.9 torr. The molecular formula of the solute is.
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