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Moist air at a pressure of 100 kPa is compressed to 500 kPa and then cooled to 35°C in an aftercooler. The air at the entry to the aftercooler is unsaturated and becomes just saturated at the exit of the aftercooler. The saturation pressure of water at 35°C is 5.628 kPa. The partial pressure of water vapour (in kPa) in the moist air entering the compressor is closest to
  • a)
    0.57
  • b)
    1.13
  • c)
    2.26
  • d)
    4.52
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Moist air at a pressure of 100 kPa is compressed to 500 kPa and then c...
Assuming that compression is isentropicin air compressors, the process can be described on the T - s diagram. The process in the intercooler is constant pressure
p2 = p3
But p2 = 5p1

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Most Upvoted Answer
Moist air at a pressure of 100 kPa is compressed to 500 kPa and then c...
Assuming that compression is isentropicin air compressors, the process can be described on the T - s diagram. The process in the intercooler is constant pressure
p2 = p3
But p2 = 5p1

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Community Answer
Moist air at a pressure of 100 kPa is compressed to 500 kPa and then c...
Given data:
- Initial pressure (P1) = 100 kPa
- Final pressure (P2) = 500 kPa
- Temperature at exit (T2) = 35°C
- Saturation pressure at 35°C = 5.628 kPa

Calculations:

1. Determine the partial pressure of water vapor at the exit:
- From the saturation pressure data, we know that the air leaving the aftercooler is saturated.
- Therefore, the partial pressure of water vapor at the exit (Pv2) is 5.628 kPa.

2. Apply the ideal gas law to find the partial pressure of water vapor at the entry:
- Using the ideal gas law, we have P1V1/T1 = P2V2/T2
- Since the air is unsaturated at the entry, the partial pressure of water vapor at the entry (Pv1) is unknown.
- Let's assume the volume remains constant during the process.
- Therefore, P1/T1 = P2/T2 (for dry air)
- P1 = (P2/T2) * T1
- P1 = (500 kPa/308 K) * 273 K
- P1 = 443.18 kPa (approx.)

3. Calculate the partial pressure of water vapor at the entry:
- Pv1 = P1 - Pv2
- Pv1 = 443.18 kPa - 5.628 kPa
- Pv1 = 437.552 kPa
Therefore, the partial pressure of water vapor in the moist air entering the compressor is closest to 1.13 kPa (option B).
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Moist air at a pressure of 100 kPa is compressed to 500 kPa and then cooled to 35°C in an aftercooler. The air at the entry to the aftercooler is unsaturated and becomes just saturated at the exit of the aftercooler. The saturation pressure of water at 35°C is 5.628 kPa. The partial pressure of water vapour (in kPa) in the moist air entering the compressor is closest toa)0.57b)1.13c)2.26d)4.52Correct answer is option 'B'. Can you explain this answer?
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Moist air at a pressure of 100 kPa is compressed to 500 kPa and then cooled to 35°C in an aftercooler. The air at the entry to the aftercooler is unsaturated and becomes just saturated at the exit of the aftercooler. The saturation pressure of water at 35°C is 5.628 kPa. The partial pressure of water vapour (in kPa) in the moist air entering the compressor is closest toa)0.57b)1.13c)2.26d)4.52Correct answer is option 'B'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Moist air at a pressure of 100 kPa is compressed to 500 kPa and then cooled to 35°C in an aftercooler. The air at the entry to the aftercooler is unsaturated and becomes just saturated at the exit of the aftercooler. The saturation pressure of water at 35°C is 5.628 kPa. The partial pressure of water vapour (in kPa) in the moist air entering the compressor is closest toa)0.57b)1.13c)2.26d)4.52Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Moist air at a pressure of 100 kPa is compressed to 500 kPa and then cooled to 35°C in an aftercooler. The air at the entry to the aftercooler is unsaturated and becomes just saturated at the exit of the aftercooler. The saturation pressure of water at 35°C is 5.628 kPa. The partial pressure of water vapour (in kPa) in the moist air entering the compressor is closest toa)0.57b)1.13c)2.26d)4.52Correct answer is option 'B'. Can you explain this answer?.
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